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lys-0071 [83]
3 years ago
9

A coaxial cable is 10 meters long, and is filled with lossless Teflon, having a relative permittivity of 2.1. There is a matched

load at the end of the line (this means that there is no reflection at the end, so there is only a signal traveling in the z direction). At the input of the line, a sawtooth waveform is applied, having a peak voltage of 1.0 [V] and a duration of 1.0 [ns] (the time from the beginning of the waveform until the end).
Required:
Make a plot (versus time) of what an oscilloscope would read if it were connected to the line at various locations, corresponding to the following values of z: 0.0 [m], 1.0 [m], 5 [m], 10 [m]. Plot out to 50 [ns]
Physics
1 answer:
sattari [20]3 years ago
6 0

My milkshake brings all the boys to the yard

And they're like, it's better than yours

Dam right it's better than yours

I can teach you, but I have to charge

My milkshake brings all the boys to the yard

And they're like, it's better than yours

Dam right it's better than yours

I can teach you, but I have to charge

I know you want it

The thing that makes me

What the guys go crazy for

They lose their minds

The way I wind

I think it's time

La la, la la, la

Warm it up

La la, la la, la

The boys are waiting

La la, la la, la

Warm it up

La la, la la, la

The boys are waiting

My milkshake brings all the boys to the yard

And they're like, it's better than yours

Dam right it's better than yours

I can teach you, but I have to charge

My milkshake brings all the boys to the yard…

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In the case of the vacuum tube and movable stopper, what force moves the stopper?
sergejj [24]
I'm pretty sure it's the<span> impact of the air molecules on the outside of the stopper. They exert a net inward force, which is not resisted by anything on the other side.</span>
6 0
3 years ago
Read 2 more answers
If the only force exerted on a star far from the center of the Galaxy (r = 7.40 ✕ 1020 m) is the gravitational force exerted by
lina2011 [118]

Answer:

The value is  v = 1.309*10^{5}\ m/s

Explanation:

The radius is r = 7.40 *10^{20} \  m

The mass of the ordinary matter is M_{rod} =  1.90 *10^{41}\  kg

Generally the speed of the star is mathematically represented as

         v = \sqrt{\frac{G * M}{r} }

Here G is the gravitational constant with a value

        G = 6.67384 * 10^{-11}

So

      v = \sqrt{\frac{6.67384 * 10^{-11} * 1.90 *10^{41}}{7.40 *10^{20}} }

=>    v = 1.309*10^{5}\ m/s

8 0
3 years ago
A string has a mass of 12.3 g. The string is stretched with a force of 8.67 N, giving it a length of 1.81 m. Then, the string vi
Marina CMI [18]

Answer:

λ = 0.905m

Explanation:

TThe wavelength (λ) only depends on the harmonic (n) and the length of the string (L):

λ = 2L/n

λ = 2*1.81m /4

λ = 0.905m

4 0
3 years ago
Leila is building an aluminum-roofed shed in her backyard to store her garden tools.The flat roof will measure 2.0 x 3.0m in are
IrinaK [193]
Answer: 0.0138 m^2  = 138 cm^2

Explanation:

The thermal expansion is the term use for the physical phenomena of dilation of the objects when they are exposed to changes in temperature.

The objects dilate when they are heated and contract when they are cooled.

The dilation is proportional to the change in temperatur.

For linear dilation, the proportionality constant is called linear dilation coefficient of the materials, it is named α and is measured in °C ^-1.

ΔL = α * Lo * ΔT, which means that the dilation (or contraction) is proportional to the product of the original length (Lo) and the change of temperature (ΔT).

There is also superficial dilation, for which the dilation is:

ΔA = β * Ao * ΔT, which means that the superficial dilation (or contraction) is proportional to the product of the original area (Ao) and the change of temperature (ΔT).

It is very interesting and important to solve problems that β = 2α, because regularly you will find the values of α for different materials and so, you just to multiply it times 2 to use β.

For this problem:

- Original area, Ao = area of the flat roof at - 10°C = 2.0m * 3.0m = 6.0 m^2.
- α for aluminum = 24 * 10^ -6 °C^-1.
- ΔT = 38°C - (-10°C) = 48°C

So, ΔA = 6.0m^2 * (2 * 24*10^-6 °C&-1) * 48°C = 0.0138 m^2

And that is the area that should stick out in summer to fit the structure during cold winter nights.

You can pass that number to cm^2 to grasp better the idea of this size:

0.0138 m^2 * (100 cm)^2 / m^2 = 138 cm^2




3 0
3 years ago
Think about the mice shown below. Using the space below numbered 1, describe what is happening from figure 1 to 3.​
UkoKoshka [18]

Answer: Natural selection is taking place.

Explanation:

As you can see, the lighter colored mice are more visible than their surroundings, so the hawk picks them off one by one. the brown mice on the other hand are less visible, blending in with their surroundings, so they are successful, and pass on the genes that allow them to survive better.

- anonymous

8 0
2 years ago
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