Answer:
nop
Explanation:
porqUE todo sería un desastre
Answer:
B) 1.65
Explanation:
See the image uploaded for the percent error formula
Work:
Theoretical Value - Accepted Value/Accepted Value * 100
= (24.7-24.3)/24.3 * 100
= 0.4/24.3 * 100
= 0.0164609053 * 100
= 1.64609053
Can be rounded to 1.65%
Part 1 : Answer is only B substance is soluble in water.
In this experiment undissolved mass of each substance was measured. According to the given data, undissolved mass of substance B at 20 °C is 10 g while A is 50 g. Since, the initial added mass of each substance is 50 g, we can see that substance A is not soluble in water since the undissolved mass is 50 g.
Part 2 : Substance A is not soluble in water and substance B is soluble in water.
According to the given data, the undissolved mass of substance A remains as same as initial added mass, 50 g throughout the temperature range from 20 ° to 80 °C. Hence, we can conclude that substance A is not soluble in water.
But, according to the data, undissolved mass of substance B at 20 °C is 10 g. That means, 40 g of substance B was dissolved in water. When the temperature increases the undissolved mass of substance B decreases. Hence, we can conclude that substance B is soluble in water and solubility increases with temperature.
