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vladimir2022 [97]
2 years ago
10

You have a radioactive isotope with a mass of 400 grams. The sample has a half life of 5 days. How much is left after 25 days ha

ve passed?
Chemistry
1 answer:
Alexeev081 [22]2 years ago
4 0

Answer:

Amount left after 25 days = 12.5 g

Explanation:

Given data:

Mass of sample = 400 g

Half life of sample = 5 days

Mass left after 25 days = ?

Solution:

First of all we will calculate the number of half lives passes in given time period.

Number of half lives = Time elapsed / Half life

Number of half lives = 25 days/ 5 days

Number of half lives = 5

At time zero = 400 g

At 1st half life = 400 g/2 = 200 g

At 2nd half life = 200 g/2 = 100 g

At 3rd half life = 100 g/2 = 50 g

At 4th half life = 50 g/2 = 25 g

At 5th half life = 25 g/2 = 12.5 g

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Ascorbic acid (H2C6H6O6; H2Asc for this problem), known as vitamin C, is a diprotic acid (Ka1= 1.0x10–5 and Ka2= 5x10–12) found
Igoryamba

Answer:

The concentrations are :

[HAsc^-]=0.000702 M

[Asc^{2-}]=5.92\times 10^{-8} M

The pH of the solution is 3.15.

Explanation:

H_2Asc\rightleftharpoons HAs^-+H^+         K_{a1}=1.0\times 10^{-5}

Initial

c                0              0

Equilibrium

c-x                x          x

K_{a1}=\frac{[HAs^-][H^+]}{[H_2Asc]}

1.0\times 10^{-5}=\frac{x\times x}{(c-x)}

1.0\times 10^{-5}=\frac{x^2}{(0.050-x)}

Solving for x:

x = 0.000702 M

[HAsc^-]=0.000702 M

HAsc^-\rightleftharpoons As^{2-}+H^+        K_{a2}=5\times 10^{-12}

Initially

x                0          0

At equilibrium ;

(x - y)            y         y

K_{a2}=\frac{[As^{2-}][H^+]}{[HAsc^-]}

5\times 10^{-12}=\frac{y\times y}{(x-y)}

5\times 10^{-12}=\frac{y^2}{(x-y)}

Putting value of x = 0.000702 M

5\times 10^{-12}=\frac{y^2}{(0.000702 -y)}

y=5.92\times 10^{-8} M

[Asc^{2-}]=5.92\times 10^{-8} M

Total concentration of [H^+]=x+y=0.000702 M+5.92\times 10^{-8} M=7.0206\times 10^{-4} M

The pH of the solution :

pH=-\log[H^+]

pH=-\log[7.0206\times 10^{-4} M}=3.15

7 0
3 years ago
What chemical process is used to convert oils into fats and semi solids
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2 years ago
How are continental drift and plate tectonics related
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5 0
2 years ago
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3 0
3 years ago
How many particles are in 3.2 mole of neon gas
Cerrena [4.2K]

There are 1.93 x 10²⁴ particles

<h3>Further explanation</h3>

Given

3.2 moles of Neon gas

Required

Number of particles

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

<em>1 mol = 6.02.10²³ particles </em>

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

So the number of particles for 3.2 moles :

N = 3.2 x 6.02.10²³

N = 1.93 x 10²⁴

or

we can describe it using Avogadro's number conversion factor

\tt 3.2~moles\times \dfrac{6.02\times 10^{23}}{1~mole}=1.93\times 10^{24}

7 0
3 years ago
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