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sergejj [24]
3 years ago
12

I NEED AN ANSWER RIGHT NOW!!! ILL GIVE BRAINLIEST TO FASTEST ANSWER!

Chemistry
1 answer:
Novay_Z [31]3 years ago
8 0

Answer:

Explanation:

hi there someone reported my answer

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Methane is the chief constituent of petroleum fuel <br> A:yes <br> B:no
Ad libitum [116K]
Yes

Methane also is the chief constituent of natural gas, which contains from 50 to 90 percent methane (depending on the source), and occurs as a component of firedamp (flammable gas) along coal seams.
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3 years ago
What do you mean by chemical reaction ?​
kherson [118]

A chemical reaction is a reaction that changes the molecular structure and is normally irreversible.

6 0
3 years ago
What In the formula Na3PO4 how many moles of sodium? How many moles of phosphorus? How many moles of oxygen?
yulyashka [42]
Sodium is Na, so there's 3 moles of that. Phosphorus is P, there's 1 mole of that. Oxygen is O, there's 4 moles of that.
5 0
3 years ago
At 0 degrees Celsius, a gas occupies 22.4L. How hot must the gas be in celcius to reach a volume of 25.0L
NikAS [45]

Answer:

31.7 °C

Explanation:

Charles law states that for volume of a gas is directly proportional to the absolute temperature for a fixed amount of gas at constant pressure

we can use the following equation

V1/T1 = V2/T2

where V1 is volume and T1 is temperature at first instance

V2 is volume and T2 is temperature at second instance

temperature should be in kelvin scale

T1 - 0 °C + 273 = 273 K

substituting the values in the equation

22.4 L / 273 K = 25.0 L / T2

T2 = 304.7 K

temperature in celcius is - 304.7 K - 273 = 31.7 °C

the gas must be 31.7 °C to reach a volume of 25.0 L

7 0
3 years ago
An empty container weighs 80.21 g. it is filled with 20.14 mL of an unknown liquid, and the total weight of the container and li
tatiyna

Answer:

1.242 g/mL

Explanation:

Step 1: Given data

Mass of the empty container (m₁): 80.21 g

Mass of the filled container (m₂): 105.22 g

Volume of the unknown liquid (V): 20.14 mL

Step 2: Calculate the mass of the liquid

The mass of the liquid is equal to the difference between the mass of the filled container and the mass of the empty container.

m = m_2 - m_1 = 105.22g - 80.21 g = 25.01 g

Step 3: Calculate the density of the unknown liquid

The density of the liquid is equal to its mass divided by its volume.

\rho = \frac{m}{V} = \frac{25.01g}{20.14mL} = 1.242 g/mL

4 0
3 years ago
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