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Naddik [55]
3 years ago
12

A 0.390 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 75.0 pC charge on it

s surface. What is the potential (in V) near its surface
Physics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

V = 346.15 Volts

Explanation:

Given that,

Diameter of the sphere, d = 0.390 cm

Radius, r = 0.195 cm

Charge, q=75\ pC =75\times 10^{12}\ C

The electric potential near its surface is given by :

V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 75\times 10^{-12}}{0.195\times 10^{-2}}\\\\V=346.15\ V

So, the potential near its surface is equal to 346.15 V.

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