Answer: Molarity of the prepared solution is 
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
where,
n= moles of solute
= volume of solution in ml = 500 ml
moles of solute =
Now put all the given values in the formula of molarity, we get
Thus molarity of the prepared solution is
The equation that best represents the behavior of acetic acid in water is; CH3CO2H + H2O ⇄ CH3CO2− + H3O+.
Acetic acid, like all other acids dissociates in water. The equation for the dissociation of acetic acid in water is; CH3CO2H + H2O ⇄ CH3CO2− + H3O+.
During this dissociation, the acid proton in acetic acid is transferred to water to form the oxonium ion H3O+.
The presence of H3O+ in solution accounts for all the observed properties of acetic acid in solution.
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Group 2 because the outer electrons ( also known as valence electrons) are 2 and that’s how we know which group it is in
2.50 x 2/1 = 5 mol of Citric Acid
5 x (3+72+5+112) = 960g of Citric Acid
Answer: 960g of Citric Acid
