In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
(1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit
In our problem,
while the width of the central maximum on the screen corresponds to twice the distance of the first minimum from the center, and it is equal to
Therefore the distance of the first minimum from the center is
If we plug these numbers into eq.(1), we can find D, the distance of the screen from the slit:
Answer:
"Force is defined as a push or pull on an object resulting from the object's interaction with another object. Displacement is the distance and direction an object is moved. Force and work are directly proportional to each other, while force and displacement are indirectly proportional."
Explanation:
*Hope this helps*
Answer:
The kinetic energy would also be increased by 138 times.
Explanation:
Rest mass of an electron
Convert to MeV
Total energy of the electron = 138×mc² =70.518 MeV
Kinetic energy of an electron
E = mc²
According to the question
E = 138×0.511 MeV = 70.518 MeV
So, the kinetic energy would also be increased by 138 times.
Answer:
The hill should be not less than 0.625 m high
Explanation:
This problem can be solved by using the principle of conservation of mechanical energy. In the absence of friction, the total mechanical energy is conserved. That means that
is constant, being U the potential energy and K the kinetic energy
When the car is in the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.
The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.
We can solve for h:
The hill should be not less than 0.625 m high
Answer:
Stephen William Hawking
Explanation:
Stephen William Hawking was a popular theoretical physicist born on 8th January 1942.
He served as the professor of mathematics at the Cambridge university
He was director at the center for theoretical cosmology.
He has theorized that the black holes will emit radiations and the radiations is known by his name Hawking's radiation.
His book 'The Brief History of Time' appeared as one of the best seller according to the Sunday Times.
Hawking's was diagnosed for a rare disease named as motor neuron disease.
He received numerous awards and elected as the fellow of royal society.
He passed away on 14th March 2018.