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sp2606 [1]
3 years ago
5

Which force links electricity and magnetism together?​

Physics
1 answer:
xenn [34]3 years ago
4 0

Answer:

the electromagnetic force

You might be interested in
Metodo medible que no altera la composicion quimica de la materia o cuerpo?
SCORPION-xisa [38]

Answer:

Las propiedades físicas, como la dureza y el punto de ebullición, y los cambios físicos, como la fusión o la congelación, no implican un cambio en la composición de la materia.

Explanation:Creo que es correcta

3 0
3 years ago
For each star, determine how its light would be shifted. Not all choices may be used, and some may be used more than once. A red
barxatty [35]

Answer:

Explanation:

To calculate the red shift you use the following formula:

z=\frac{1+vcos\theta/c}{\sqrt{1-v^2/c^2}}-1

\tetha: angle between the observer and the motion of the body

v: speed of the body

c: speed of light

for motion with angle 90° (transversal motion):

z=\sqrt{\frac{c+v}{c-v}}-1

- A red dwarf moving away from Earth at 39.1 km/s :

z=\sqrt{\frac{3*10^8m/s+39.1*10^3m/s}{3*10^8m/s-39.1*10^3m/s}}-1=1.3*10^{-4}

- A yellow dwarf moving transversely at 15.1 km/s (angle = 90°):

z=\frac{1+0}{\sqrt{1-(15.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.27*10^{-9}

- A red giant moving towards Earth at 23.3 km/s (angle = 0°):

z=\frac{1+(23.3*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(23.3*10^3m/s)^2/(3*10^8m/s)^2}}-1=7.76*10^{-5}

- A blue dwarf moving away from Earth at 25.9 km/sz=\frac{1+(25.9*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(25.9*10^3m/s)^2/(3*10^8m/s)^2}}-1=8.63*10^{-5}

- A red dwarf moving transversely at 14.1 km/s

z=\frac{1+0}{\sqrt{1-(14.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.11*10^{-9}

6 0
4 years ago
For light of wavelength 589 nm, calculate the critical angles for the following substances when surrounded by air.
NeX [460]

(1) The critical angles for the fused quartz is 44⁰,

(2) The critical angles for the polystyrene is 39⁰.

(3) The critical angles for the sodium chloride is 41⁰.

<h3>What is Critical angles?</h3>

In optics, the critical angle is the topmost angle at which a shaft of light traveling in one transparent medium can strike the boundary between that medium and another with a lower refractive indicator without being fully reflected within the first

Critical angles for the different medium.

θ=sin^{-1}\frac{n_{2} }{n_{1} }

where;

n_{2} is the refractive index of air = 1

n_{1} is the refractive index of the given substances.

Refractive index of quartz glass = 1.46

Refractive index of polystyrene = 1.59

Refractive index of sodium chloride = 1.54

Critical angles for quartz glass:

$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.46}\\$

$\theta_{\text {crit }}=44^{o}$

Critical angles for polystyrene

$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.59}\\\\

\theta_{\text {crit }}=39^{\circ}

Critical angles for Sodium Chloride

$\theta_{\text {crit }}=\sin ^{-1} \frac{1.00029}{1.54}\\

\theta_{\text {crit }}=41^{o}

Thus, the critical angles for the quartz glass is 44⁰, the critical angles for the polystyrene is 39 ⁰ and the critical angles for the sodium chloride is 41⁰.

To know more about critical angle visit:
brainly.com/question/3314727

#SPJ4

I understand that the question you are looking for is:

"For light of wavelength 589 nm, calculate the critical angles for the following substances when surrounded by air.

(a) Fused Quartz

(b) Polystyrene

(c) Sodium chloride"

8 0
2 years ago
8. An airplane of mass 8500 kg dives has an altitude of 15,000 m. It then dives steeply to an
Ivan

Answer:

333.5 MJ

Explanation:

ΔV = m·g·Δh

     = 8500 · 9.81 · (15000-11000)

     = 8500 · 9.81 · 4000

     = 333 540 000

     ≈ 333.5 ·10⁶J = 333.5 MJ

8 0
3 years ago
A 13 kg rock is sitting on a cliff. If the rock has 3,500 joules of potential energy, what is the height of the cliff in meters?
Bezzdna [24]

<u>Answer:</u>

The height of the cliff in meters = 27.44

<u>Explanation:</u>

 The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.

 Here we have mass of rock = 13 kg

                          Potential energy = 3500 J

                          Acceleration due to gravity  = 9.81m/s^2

                          Substituting   3500 = 13 * 9.81 * h

                                                       h = 27.44 meter

      The height of the cliff in meters = 27.44

7 0
4 years ago
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