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Gemiola [76]
3 years ago
5

the brakes applied to a car produces an acceleration of 6m/s^2 in the opposite direction to the motion. if the car takes 2s to s

top after the application of brakes. calculate the distance it travels during this time .
Physics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

acceleration= -6ms^-2

Explanation:

v = u + at \\ 0 = u + ( - 6 \times 2) \\ u = 12m {s}^{ - 1}

distance

s = ut +  \frac{1}{2} a {t}^{2}  \\ s = 12 \times 2 +  \frac{1}{2}  \times ( - 6) \times  {2}^{2}   \\ s = 12m

<h3>therefore distance = 12m</h3>
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