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3 years ago

What volume is occupied by 8.67 grams of methane gas at STP?

1 answer:

8 0

Molar mass methane ( CH₄) = 16.04 g/mol

number of moles:

mass CH₄ / molar mass

8.67 / 16.04 => 0.5405 moles

1 mole ------------------ 22.4 L ( at STP )
0.5405 moles --------- ??

0.5405 x 22.4 / 1 => 12.1072 L

hope this helps!

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When dinitrogen pentaoxide, a white solid, is heated, it decomposes to produce nitrogen dioxide gas and

AysviL [449]

9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

Oxygen produced - 1.618 gram

Decomposition of $N_2O_5$ takes place.

Find - Amount of $NO_2$ produced.

The decomposition reaction is as follows -

$2N_2O_5$ --> $4NO_2 + O_2$

Moles of $O_2$ gas = $\frac{1.6}{16}$ =0.1 moles.

1 mole of $O_2$ is produced from 2 moles of dinitrogen pentoxide

0.1 mole of $O_2$ will be produced from = 0.2 moles.

Now, 2 moles of dinitrogen pentoxide produce 4 moles of $NO_2$

$NO_2$ produced will be - 0.4 moles.

Weight of $NO_2$ produced - 0.4 X 46

Weight of $NO_2$ produced - 18.4 gram

Thus, grams of $NO_2$ produced are 18.4

Now calculate the volume of $NO_2$

Given data are:

P=103.25 kPa =1.01899827 atm

T= 22.75 °C +273 = 295.75 K

n=0.4 moles

V=?

R= 0.0821 liter·atm/mol·K

Putting the value in PV=nRT

V = $\frac{nRT}{P}$

V = $\frac{0.4 \;moles \;X \;0.0821\; liter\;atm/\;mol \;K X \;295.75 \;K}{1.01899827 atm}$

V= 9.5314 L

Hence, 9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

Learn more about the ideal gas equation here:

brainly.com/question/13450124

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8 0

2 years ago

Chloroform has a density of 1.5 g/ml. What the mass of 10.0 ml of Chloroform?

8090 [49]

Answer:

The answer is 15 g

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density of Chloroform = 1.5 g/ml

volume = 10 mL

We have

mass = 1.5 × 10

We have the final answer as

Hope this helps you

8 0

3 years ago

Hello guys sorry for spamming again but I have to do this whole thing and the end of trimester for my school is today so I need

Aloiza [94]

Answer:

all you need if yo look up and say do plants grow without soil but yes they can grow without soil but they cannot grow without the necessities that soil provides.

4 0

3 years ago

Convert 4 x 10^-3 dL to cm^3 <br><br> Please give the work and the answer in scientific notation.

Serhud [2]

4 x $10^{-3$ in dL will be 4 x $10^{-1}$ $cm^3$

<h3>Conversion from dL to cm^3</h3>

Recall that:

Deci = $10^{-1}$

Centi = $10^{-2}$

Thus, 1 dl = 100 ml

This means that converting from dl to $cm^3$ requires multiplying by $10^2$ .

Applying this principle, 4 x $10^{-3$ in dL to $cm^3$ will be:

4 x $10^{-3$ x $10^2$ $cm^3$ = 4 x $10^{-1}$ $cm^3$

Therefore, 4 x $10^{-3$ dl will be 4 x $10^{-1}$ $cm^3$

More on volume conversion can be found here:

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3 0

2 years ago

Write the formula equation for the reaction between hydroiodic acid and beryllium hydroxide

Aleksandr-060686 [28]

The formula equation for the reaction between hydroiodic acid and beryllium hydroxide is as below

Be(OH)2 + 2 HI = BeI2 + 2H2O

Formula of hydroiodic is = HI
formula of beryllium hydroxide = Be(OH)2

1 mole of Be(OH)2 react with 2 mole of HI to form 1 mole of BeI2 and 2 mole of H2O

8 0

4 years ago