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HACTEHA [7]
3 years ago
11

Help me please I will give u a brainlist!!!

Engineering
1 answer:
Sloan [31]3 years ago
5 0

Explanation:

Frequency=1/period

approximately= 0.16 Hz

f =  \frac{1}{t}  =  \frac{1}{6.3}  = 0.158 \: hz = 0.16 \: hz

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All MOS devices are subject to damage from:________
Alchen [17]

Answer:

  d. all of these

Explanation:

Electrostatic discharge will generally produce excess voltage in a local area that results in excessive current and excessive heat. It will blast a crater in an MOS device, or melt bond wires, or cause damage of other sorts. In short, MOS devices are subject to damage from "all of these."

6 0
3 years ago
Need help with these 3 questions pls help
Anton [14]

Answer:

I think 5 is passion and 6 is true I think and 7 is time management I'm pretty sure

3 0
3 years ago
A(n) ___ is an electric device that uses electromagnetism to change (step up or step down) AC voltage from one level to another.
Pie

Answer:

A transformer is an electric device that uses electromagnetism to change voltage from one level to another or to isolate one voltage from another.

7 0
3 years ago
A 12-ft high retaining wall has backfill of granular soil with an internal angle of friction of 30 and unit weight of 125 pef. W
irakobra [83]

Answer:

P_p = 27000 psf

Explanation:

given,

height of the retaining wall = h = 12 ft

internal angle of friction (∅)= 30°

unit weight = 125 pcf

Rankine passive earth pressure = ?

k_p is the coefficient of passive earth pressure

k_p = \dfrac{1 + sin\phi}{1 - sin\phi}

k_p = \dfrac{1 + sin30^0}{1 - sin30^0}

k_p = 3

Passive earth pressure

P_p = \dfrac{1}{2}k_p \gamma H^2

P_p = \dfrac{1}{2}\times 3\times 125 \times 12^2

      P_p = 27000 psf

Rankine passive earth pressure on the wall is equal to P_p = 27000 psf

7 0
3 years ago
An add tape of 101 ft is incorrectly recorded as 100 ft for a 200-ft distance. What is
baherus [9]

Answer:

the correct distance is 202 ft

Explanation:

The computation of the correct distance is shown below:

But before that correction to be applied should be determined

= (101 ft - 100 ft) ÷ (100 ft) × 200 ft

= 2 ft

Now the correct distance is

= 200 ft +  2 ft

= 202 ft

Hence, the correct distance is 202 ft

The same would be relevant and considered too

4 0
3 years ago
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