1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
HACTEHA [7]
3 years ago
11

Help me please I will give u a brainlist!!!

Engineering
1 answer:
Sloan [31]3 years ago
5 0

Explanation:

Frequency=1/period

approximately= 0.16 Hz

f =  \frac{1}{t}  =  \frac{1}{6.3}  = 0.158 \: hz = 0.16 \: hz

You might be interested in
A lake has a carrying capacity of 10,000 fish. At the current level of fishing, 2,000 fish per year are taken with the catch uni
arlik [135]

Answer:

The population size would be p' = 5000

The yield would be    MaxYield = 2082 \ fishes \ per \ year

Explanation:

So in this problem we are going to be examining the application of a  population dynamics a fishing pond and stock fishing and objective would be to obtain the maximum sustainable yield and and the population of the fish at the obtained maximum sustainable yield,  so basically we would be applying an engineering solution to fishing

 

    So the current  yield which is mathematically represented as

                               \frac{dN}{dt} =   \frac{2000}{1 \ year }

 Where dN is the change in the number of fish

            and dt is the change in time

So in order to obtain the solution we need to obtain the  rate of growth

    For this we would be making use of the growth rate equation which is

                                      r = \frac{[\frac{dN}{dt}] }{N[1-\frac{N}{K} ]}

  Where N is the population of the fish which is given as 4,000 fishes

          and  K is the carrying capacity which is given as 10,000 fishes

             r is the growth rate

        Substituting these values into the equation

                              r = \frac{[\frac{2000}{year}] }{4000[1-\frac{4000}{10,000} ]}  =0.833

The maximum sustainable yield would be dependent on the growth rate an the carrying capacity and this mathematically represented as

                      Max Yield  = \frac{rK}{4} = \frac{(10,000)(0.833)}{4} = 2082 \ fishes \ per \ year

So since the maximum sustainable yield is 2082 then the the population need to be higher than 4,000 so in order to ensure a that this maximum yield the population size denoted by p' would be

                          p' = \frac{K}{2}  = \frac{10,000}{2}  = 5000\ fishes          

7 0
3 years ago
Read 2 more answers
Marcus wants to pursue a career in civil engineering. He aims to work for the city council as a civil engineer. What examination
Rzqust [24]

Answer:

Marcus would have to take an exam administered by the national council of examiners for engineering and surveying.

Explanation:

Civil engineers design, construct, and maintain projects regarding infrastructure. A civil engineer also looks after the systems in the public and private sectors like roads, buildings, and systems for water supply and sewage treatment.

In order to pursue a career in civil engineering, Marcus aims to work for the city council as a civil engineer. Therefore, he would have to take an exam administered by the national council of examiners for engineering and surveying.

6 0
3 years ago
Steam enters a steady-flow adiabatic nozzle with a low inlet velocity (assume ~0 m/s) as a saturated vapor at 6 MPa and expands
Sergio [31]
Yea bro I don’t really know
7 0
3 years ago
A home electrical system is joined to the electric company's system at the junction of the
aleksandrvk [35]

That would be B, I hope this helps!

5 0
3 years ago
Given asphalt content test data:
VMariaS [17]

Answer:

hello your question is incomplete attached below is the complete question

A) overall mean = 5.535,  standard deviation ≈ 0.3239

B ) upper limit = 5.85, lower limit = 5.0

C) Not all the samples meet the contract specifications

D) fluctuation ( unstable Asphalt content )

Explanation:

B) The daily average asphalt content has to obtained in order to determine the upper and lower control limits using an average asphalt content of 5.5% +/- 0.5% everyday

The upper limit : 14 may = ( 5.8 + 5.1 ) / 2 = 5.85

The lower limit : 16 may = ( 5.2 + 4.8 ) / 2 = 5.0

attached below is the required plot

C ) Not all the samples meet the contract specifications and the samples that do not meet up are samples from :

15 may and 16 may . this is because their Asphalt contents are 6.2 and 4.8 respectively and sample number 18 and 20

D ) what can be observed is that the ASPHALT content fluctuates between the dates while the contract specification is fixed

5 0
3 years ago
Other questions:
  • Determine the required dimensions of a column with a square cross section to carry an axial compressive load of 6500 lb if its l
    12·2 answers
  • In a particular application involving airflow over a heated surface, the boundary layer temperature distribution may be approxim
    6·1 answer
  • How to solve this question
    11·1 answer
  • The Greek alphabet has 24 distinct lowercase letters. How many bits are needed to be able to encode any single lowercase Greek l
    9·1 answer
  • The water level in a large tank is maintained at height H above the surrounding level terrain. A rounded nozzle placed in the si
    9·1 answer
  • PLLLLLEEESSSEEE IIII NEED ASAP
    12·2 answers
  • ما جمع كلمة القوة؟help please
    10·1 answer
  • A landowner and a contractor entered into a written contract under which the contractor agreed to build a building and pave an a
    14·1 answer
  • Recommend the types of engineers needed to collaborate on a city project to build a skateboard park near protected wetlands.
    6·1 answer
  • 1<br>M<br>A BLIND COOK WHO DEFEATED<br>OVER 30,000 HOME COOKS!<br>y of​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!