Answer:
Repeated SN2 reactions occur leading to the formation of a racemic mixture
Explanation:
S-2-iodooctane is a chiral alkyl halide with an asymmetric carbon atom. The presence of an asymmetric carbon atom implies that it can rotate plane polarized light and thus lead to optical isomerism. The two configurations of the compound are R/S according to the Cahn-Prelong-Ingold system.
However, when S-2-iodooctane is treated with sodium iodide in acetone, repeated SN2 reactions occur since the iodide ion is both a good nucleophile and a good leaving group. Hence a racemic modification is formed in the system with time hence we end up with (±)- Iodooctane.
The 4th energy level (row), 's' orbital block, 2nd group (column). The valence electrons are found in the highest energy level of the electron configuration in the 's' and 'p' orbitals. In the case of calcium this is 4s2 . This gives calcium an 's' orbital with a pair of electrons in its valence shell
<u>Answer:</u> The ionic compound formed is
(barium fluoride)
<u>Explanation:</u>
Ionic compound is formed by the complete transfer of electrons from 1 atom to another atom. The cation is formed by the loss of electrons by metals and anions are formed by gain of electrons by non metals.
Taking the metal as barium and non-metal as fluorine.
Barium is the 56th element of the periodic table having electronic configuration of ![[Xe]6s^2](https://tex.z-dn.net/?f=%5BXe%5D6s%5E2)
This element will loose 2 electrons and will form
ion
Fluorine is the 9th element of the periodic table having electronic configuration of ![[He]2s^22p^5](https://tex.z-dn.net/?f=%5BHe%5D2s%5E22p%5E5)
This element will gain 1 electron and will form
ion
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
Hence, the ionic compound formed is
(barium fluoride)