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Shtirlitz [24]
3 years ago
14

Fred is conducting a controlled experiment to test whether using a grow light at night will help a tomato plant grow faster. Bel

ow are the steps to Fred's experiment: Plant tomato plants in two separate, but identical, flowerpots. Place the flowerpots in the same area outside during the day. At night, bring both flower pots inside and place one in the dark and one under a grow light. Give the plants the same amount of food and water each week. Measure the growth of the plants. Draw conclusions based on the data collected. Which of the following variables must Fred hold constant in this experiment?
Physics
1 answer:
PtichkaEL [24]3 years ago
4 0

Answer:

the type of tomato plants used.

Explanation:

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Two forces act on a 1250 kg sailboat as it moves through the water with an initial velocity of 11 m/s. The forward force of the
Naddik [55]

Answer:

The velocity of the boat 15 seconds later is 5.6 meters per second.

Explanation:

We assume that sailboat can be modelled as particle, so that we use solely translations equations. It is noticed that the sailboat is move by action of the wind and drag force of the water is opposed to such force, but the last force has a greater magnitude than the first one, meaning that net force is less than zero.

From Newton's Laws we have the following equation of equilibrium for the sailboat:

\Sigma F = F - f = m\cdot a (Eq. 1)

Where:

F - Force from the wind exerted on the sailboat, measured in newtons.

f - Drag force of the water, measured in newtons.

m - Mass of the sailboat, measured in kilograms.

a - Net acceleration of the sailboat, measured in meters per square second.

If we know that F = 3.90\times 10^{3}\,N, f = 4.35\times 10^{3}\,N and m = 1250\,kg, then the net acceleration of the sailboat is:

a = \frac{F-f}{m}

a = \frac{3.90\times 10^{3}\,N-4.35\times 10^{3}\,N}{1250\,kg}

a = -\frac{9}{25}\,\frac{m}{s^{2}}

If sailboat decelerates uniformly, then we can get the final velocity of the boat by using this equation of motion:

v = v_{o}+a\cdot t (Eq. 2)

Where:

v_{o}, v - Initial and final velocities of the sailboat, measured in meters per second.

t - Time, measured in seconds.

If we get that v_{o} = 11\,\frac{m}{s}, a = -\frac{9}{25}\,\frac{m}{s^{2}} and t = 15\,s, then the final velocity of the sailboat is:

v = 11\,\frac{m}{s} +\left(-\frac{9}{25}\,\frac{m}{s^{2}}  \right)\cdot (15\,s)

v = 5.6\,\frac{m}{s}

The velocity of the boat 15 seconds later is 5.6 meters per second.

3 0
3 years ago
Convert 1,200 meters to millimeters
Nikolay [14]

Answer:

1,200,000 millimeters

6 0
3 years ago
D. If they are dropped from their original heights at the same time, will the melon or
dsp73

Answer:

Melon

Explanation:

The melon will hit the ground first because it has a greater mass and therefore greater gravitational pull than the pomegranate, which weighs less.

5 0
3 years ago
At time t = 1, a particle is located at position (x, y) = (5, 2). If it moves in the velocity field F(x, y) = xy − 1, y2 − 11 fi
Amanda [17]

Answer:

Its approx location is (5.18,1.9)

Explanation:

Using F( 5,2) = ( xy-1, y²-11)

= ( 5*2-¹, 2²-11)

= (9,-5)

= so at point t=1.02

(5,2)+(1.02-1)*(9,-5)

(5,2)+( 0.02)*(9,-5)

(5+0.18, 2-0.1)

= ( 5.18, 1.9)

3 0
3 years ago
An amusement park ride called the Rotor debuted in 1955 in Germany. Passengers stand in the cylindrical drum of the Rotor as it
steposvetlana [31]

Answer:

μs = 0.36

Explanation:

  • While the drum is rotating, the riders, in order to keep in a circular movement, are accelerated towards the center of the drum.
  • This acceleration is produced by the centripetal force.
  • Now, this force is not a different type of force, is the net force acting on the riders in this direction.
  • Since the riders have their backs against the wall, and the normal force between the riders and the wall is perpendicular to the wall and aiming out of it, it is easily seen that this normal force is the same centripetal force.
  • In the vertical direction, we have two forces acting on the riders: the force of gravity (which we call weight) downward, and the friction force, that will oppose to the relative movement between the riders and the wall, going upward.
  • When this force be equal to the weight, it will have the maximum possible value, which can be written as follows:

       F_{frmax} = \mu_{s}* F_{n}  = m * g  (1)

  • where μs= coefficient of static friction (our unknown)
  • As  we have already said Fn = Fc.
  • The value of the centripetal force, is related with the angular velocity ω and the radius of the drum r, as follows:

      F_{n} = m* \omega^{2} * r  (2)

  • Replacing (2) in (1), simplifying and rearranging terms, we can solve for μs, as follows:

       \mu_{s} = \frac{g}{\omega^{2} r}  (3)

  • Prior to replace ω for its value, is convenient to convert it from rev/min to rad/sec, as follows:

       \omega = 26.0 \frac{rev}{min} * \frac{1min}{60 sec} *\frac{2*\pi rad }{1 rev} = 2.72 rad/sec (4)

  • Replacing g, ω and r in (3):
  • \mu_{s} = \frac{g}{\omega^{2} r} = \frac{9.8m/s2}{(2.72rad/sec)^{2} *3.7 m} = 0.36 (5)

3 0
3 years ago
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