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Shtirlitz [24]
3 years ago
14

Fred is conducting a controlled experiment to test whether using a grow light at night will help a tomato plant grow faster. Bel

ow are the steps to Fred's experiment: Plant tomato plants in two separate, but identical, flowerpots. Place the flowerpots in the same area outside during the day. At night, bring both flower pots inside and place one in the dark and one under a grow light. Give the plants the same amount of food and water each week. Measure the growth of the plants. Draw conclusions based on the data collected. Which of the following variables must Fred hold constant in this experiment?
Physics
1 answer:
PtichkaEL [24]3 years ago
4 0

Answer:

the type of tomato plants used.

Explanation:

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Clothes dryer uses about 3:00 amps of current from a 240-volt line how much power does it use
kirill115 [55]

Electrical power is defined as

P = I * V

I = 3 amperes

V = 240 volts

Power = 3 * 240

Power = 720 Watts. Answer

4 0
3 years ago
The process of bringing the solvent to boiling, evaporating it all away, and leaving the solute behind, is known as
Georgia [21]
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8 0
4 years ago
You are getting bored as you are stuck at home, and want to find out the effective 'spring constant' of random objects. You find
Luda [366]

Given Information:  

Mass of sock = 0.23 kg

Stretched length of sock = x = 2.54 cm = 0.0254 m

Required Information:  

Spring constant = k = ?

Answer:  

Spring constant = k = 88.82 N/m

Explanation:  

We know from the Hook's law that

F = kx

Where k is spring constant, F is the applied force and x is length of sock being stretched.

k = F/x

Where F is given by

F = mg

F = 0.23*9.81

F = 2.256 N

So the spring constant is

k = 2.256/0.0254

k = 88.82 N/m

Therefore, the spring constant of the sock is 88.82 N/m

4 0
3 years ago
Read 2 more answers
Four hundred seventy joules of heat are removed from a heat reservoir at a temperature of 470 K. What is the entropy change of t
11111nata11111 [884]

Answer:

ΔS= -1 J/K

Explanation:

Given data

Heat Q= -470J

Temperature T=470 K

To find

Entropy change ΔS

Solution

We know that the entropy change of system is ΔS is given by

ΔS=Q/T

We have take heat value Q as negative because the heat is removed from heat reservoir

So

ΔS=(-470J/470K)

ΔS= -1 J/K

8 0
3 years ago
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Esercizio 1
timama [110]

Explanation:

can u please translate it to english language. I can't understand.

7 0
3 years ago
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