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docker41 [41]
3 years ago
10

I WILL GIVE U 100 POINTS IF U COMPLETE THIS AND GET RIGHT!!!!!!!!!!!!

Physics
1 answer:
Alchen [17]3 years ago
8 0

Answer:

A.

1. when the butter was placed on the spoon it slowly started to boil then began to melt.

2.the order was to heat the bowl, let it boil, then place the butter in.

3.The heat got from the water to the butter by placing it on the spoon then physically moving it into the hot bowl.

4.objects that do not conduct heat are called insulators.

B.

1. When the ice cube got placed into the water it immediately melted.

2.the water from the ice cube to the warm water as soon as it got laced it immediately melted.

3. the heat flowed straight up which made the ice melt really fast.

TABLE A: when I placed the butter in it melted a little bit slower than the ice cube but it still melted very fast.

TABLE B: when I put the colored one in the color slowly dissolved and pushed the color to the middle and the cube melted.

TABLE C: room temp water:75 degrees

cold water:50

hot water:315 degrees

TABLE D: when I blew out the candle the flame went but the smoke started to rise up.

TABLE E: the small beaker heated up quicker and I observed that the less amount of mass the faster it will heat up.

TABLE F: the black piece of paper heated up quicker and I believe its because the darker color the more mount of heat is attracted.

Explanation: I HOPE THIS HELPED! BRAINLESS?

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I cant solve this problem, and our teacher said that this would be in the test we'll have tomorrow, can someone help me?
Ad libitum [116K]

Answer:

d = 11.1 m

Explanation:

Since the inclined plane is frictionless, this is just a simple application of the conservation law of energy:

\frac{1}{2} m {v}^{2}  = mgh

Let d be the displacement along the inclined plane. Note that the height h in terms of d and the angle is as follows:

\sin(15)  =  \frac{h}{d}  \\ or \: h = d \sin(15)

Plugging this into the energy conservation equation and cancelling m, we get

{v}^{2}  = 2gd \sin(15)

Solving for d,

d =  \frac{ {v}^{2} }{2g \sin(15) }  =  \frac{ {(7.5 \:  \frac{m}{s}) }^{2} }{2(9.8 \:  \frac{m}{ {s}^{2} })(0.259)}   \\ = 11.1 \: m

3 0
3 years ago
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Dafna1 [17]
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weqwewe [10]
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