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dusya [7]
3 years ago
5

Which substance is the limiting reactant when 4.0 g of sulfur reacts with 6.0 g of oxygen and 8.0 g of sodium hydroxide accordin

g to the following chemical equation: 2 S(s) + 3 O2(g) + 4 NaOH(aq) → 2 Na2SO4(aq) + 2 H2O(l)
A. O2(g)
B. S(s)
C. NaOH(aq)
D. None of these substances is the limiting reactant.
Chemistry
1 answer:
Marysya12 [62]3 years ago
6 0
C, NaOH(aq) is the answer
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Determine the [H3O+] in a 0.265 M HClO solution. The Ka of HClO is 2.9 × 10-8.
dexar [7]

8.8 × 10-5 M is the  [H3O+] concentration in 0.265 M HClO solution.

Explanation:

HClO is a weak acid and does not completely dissociate in water as ions.

the equation of dissociation can be written and ice table to be formed.

 HClO +H2O ⇒ ClO- + H3O+

I  0.265                0        0

C  -x                    +x     +x

E  0.265-x          +x      +x

Now applying the equation of Ka, where Ka is given as 2.9 × 10-8.

Ka = \frac{[ClO-][H3O+]}{[HClO]}

2.9 × 10^-8 = \frac{[x] [x]}{[0.265-x]}

x^{2} = 7.698 x10^{-9}

x = 8.8 × 10-5 M

The hydronium ion concentration is 8.8 × 10-5 M  in 0.265 M solution of HClO.

8 0
2 years ago
Timothée Chalamet is hot
Elza [17]
False. harry styles all the way
8 0
2 years ago
Read 2 more answers
Redox 1/2 reaction Cu(s) + 2 AgC2H3O2(aq) = Cu(C2H3O2)2(aq) + 2 Ag(s)
Anna11 [10]

Explanation:

 Reaction:

              Cu  +     2AgC₂H₃O₂     →    Cu(C₂H₃O₂)₂    +     2Ag

The problem is to split the reaction into oxidation and reduction halves:

 The oxidation half is the sub-reaction that undergoes oxidation

  The reduction half is the one that undergoes reduction:

The ionic equation:

 Cu   +  2Ag⁺   +   2C₂H₃O₂⁻   →   Cu²⁺  +  2C₂H₃O₂⁻   +  2Ag

Oxidation half:

     Cu →  Cu²⁺ + 2e⁻

 

Reduction half:

    2Ag⁺ + 2e⁻ → 2Ag

C₂H₃O₂⁻ is neither oxidized nor reduced in the reaction.

learn more:

Oxidation state brainly.com/question/10017129

#learnwithBrainly

4 0
3 years ago
3. If you start with 8x1025 molecules of Cl, and 25 grams of KI, how many grams of KCl would
miskamm [114]

Answer:

Percent yield = 89.1%

Explanation:

Based on the equation:

Cl₂ + 2KI → 2KCl + I₂

<em>1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl</em>

<em />

To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:

<em>Moles Cl₂:</em>

8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles

<em>Moles KI -Molar mass: 166.0028g/mol-</em>

25g * (1mol / 166.0028g) = 0.15 moles

Here, clarely, the KI is the limiting reactant

As 2 moles of KI produce 2 moles of KCl, the moles of KCl produced are 0.15 moles. The theoretical mass is:

0.15 moles * (74.5513g / mol) =

11.2g KCl

Percent yield is: Actual yield (10.0g) / Theoretical yield (11.2g) * 100

<h3>Percent yield = 89.1%</h3>
3 0
3 years ago
a block of wood has a density of 0.95 g/cm3. will it float or sink when placed on a liquid with a density of 0.88 g/mL? explain
vesna_86 [32]
Since 1mL=1cm^3 the wood would sink due to it being more dense. I.e. 0.95>0.88
3 0
3 years ago
Read 2 more answers
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