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3 years ago

How do you figure out cos and sin?

Physics

2 answers:

Nataly_w [17]3 years ago

6 0

Answer:

In a right triangle, you always want to use the right angle as a reference. Sin is opposite side over hypotenuse, and cos is adjacent side over hypotenuse. An easy way to remember is SOHCAHTOA (Sin Opposite Hypotenuse, Cos Adjacent Hypotenuse, Tan Opposite Adjacent), The acronym I use to remember this is "Some old hippy caught another hippy tripping on acid."

Explanation:

dexar [7]3 years ago

5 0

Answer:this is all i can give you

Explanation:

1.The sine of the angle = the length of the opposite side. the length of the hypotenuse.

2.The cosine of the angle = the length of the adjacent side. the length of the hypotenuse.

3.The tangent of the angle = the length of the opposite side. the length of the adjacent side.

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Why is copper a good conductor?

IgorLugansk [536]

Copper conducts electricity

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3 years ago

Read 2 more answers

A basketball player shoots toward a basket 4.9 m away and 3.0 m above the floor. If the ball is released 1.8 m above the floor a

Zolol [24]

Answer:

v₀ = 6.64 m / s

Explanation:

This is a projectile throwing exercise

x = v₀ₓ t

y = y₀ + v_{oy} t - ½ g t²

In this case they indicate that y₀ = 1.8 m and the point of the basket is x=4.9m y = 3.0 m

the time to reach the basket is

t = x / v₀ₓ

we substitute

y- y₀ = $\frac{ v_o \ x \ sin \theta }{ v_o \ cos \theta} - \frac{1}{2} g \ \frac{x^2 }{v_o^2 \ cos^2 \theta }$

y - y₀ = x tan θ - $\frac{ g \ x^2 }{ 2 \ cos^2 \theta } \ \frac{1}{v_o^2 }$

we substitute the values

3 -1.8 = 3.0 tan 60 - $\frac{ 9.8 \ 3^2 }{2 \ cos^2 60 } \ \frac{1}{v_o^2}$

1.2 = 5.196 - 176.4 1 / v₀²

176.4 1 / v₀² = 3.996

v₀ = $\sqrt{ \frac{ 176.4}{3.996} }$

v₀ = 6.64 m / s

6 0

3 years ago

How do scientists construct models of atoms and molecules?

9966 [12]

Mr. Roentgen's x-rays allowed scientists to measure the size of the atom. The x-rays were small enough to discern the atomic clouds. This was done by scattering x-rays from atoms and measuring their size just as Rutherford had done earlier by hitting atoms with other nuclei starting with alpha particles.

6 0

3 years ago

Consider the resistances of short and open circuits. Fill in the blanks: The voltage across a short circuit will always be _____

aleksandr82 [10.1K]

Answer:

a) Zero

b) power source

Explanation:

According to Ohm's law, the voltage dropped in a resistance is proportional to the current flow and the resistor opposing to it.

$V=I*R$

For the case of a short circuit, the resistance tends to zero, so the voltage will tend to zero too.

In the case of the open circuit, the resitance will tend to infinity, because we cannot obtain an infite voltage, it will be limited by the power source.

3 0

3 years ago

Consider the program below:public class Test{ public static void main(String[] args) {Int[] a;a = new int[10];for(int i = 0; i &

ivolga24 [154]

Answer:

c. 65

Explanation:

The output is 65.

An array of length 10 is created first. Then, the first for-loop fill the array with different values; The array element now become: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11. The array element are generated using the equation a[i] = i + 2; so when i is 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. i must be less than the array length (10).

a[0] = 0 + 2 = 2

a[1] = 1 + 2 = 3

a[2] = 2 + 2 = 4

a[3] = 3 + 2 = 5

a[4] = 4 + 2 = 6

a[5] = 5 + 2 = 7

a[6] = 6 + 2 = 8

a[7] = 7 + 2 = 9

a[8] = 8 + 2 = 10

a[9] = 9 + 2 = 11

result variable is declared and initialized to 0.

The second for-loop goes through the array and add individual element to result.

6 0

3 years ago