The ksp value for calcium hydroxide at this temperature is 5.20 × 10⁻⁶.
<h3>What is ksp?</h3>
Ksp is an equilibrium constant of a solid substance dissolved in a liquid solution.
Given that, the volume of water is 0.178 l, 0.264 g of Ca(OH)² dissolves in enough water
The solution equilibrium is
Ca(OH)² = Ca + 2OH
The molar solubility is
0.186 / 74.00 / 0.230 = 0.0109 M
The ksp value will be
Ksp = (s) (2S)²
Putting the values in the formula
(0.0109) x (2 x 0.0109)² = 5.20 × 10⁻⁶.
Thus, the ksp value for calcium hydroxide is 5.20 × 10⁻⁶.
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I think the correct answer is C
Answer:
The concentration of N2O4(g) and the concentration of NO2(g) must be constant
Explanation:
A system at equilibrium as described by this equation
N2O4(g) <-------> 2 NO2 (g), shows that the concentration of N2O4 (g) and the concentration of NO2 (g) is constant. This is true because the rate at which the forward reaction is occurring that is N2O4 giving NO2 is the same as the rate at which the reverse reaction is occurring. At this point, the concentration of both substances is not changing but constant. In this type of reaction, reactions are still occurring in the system but there is no overall change in the concentrations of the substances involved.
When we plot a concentration and time graph, at a point in time we can see that the concentrations does not change (remains constant)
At any given time t:
Rate (forward) = k[N
2
O
4] = -
Δ[N
2O
4] / Δ
t
Rate (reverse) = k[NO
2]2 = -
Δ[NO
2] / Δ
t
Answer:
Explanation:
The first two are easy:
H2O, H3O+ and OH- all exist in an equilibrium
[H3O+] = [OH-] = 10^-7 M
HCl is a strong acid so 1M of it will disassociate completely
[H3O+] = [Cl-] = 1 M
The third one is also an equilibrium as HNO2 is a weak acid. Ka is given so [HNO2] and [NO2-] can be calculated.
The fourth one is a buffer solution so its pH can be looked up to give the concentrations.