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Kay [80]
3 years ago
7

If 2 people are on a bed and they are the same weight, and 1 of them gets off and the bed breaks who is responsible? Is it the p

erson still on the bed or the person who got off?
Physics
1 answer:
alekssr [168]3 years ago
6 0

Answer:

I would say the one who got up bc if he or she wouldn't have gotten up the bed wouldn't have broke

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Magma from a volcano is considered a fluid because it can flow and it exhibits viscosity true or false
PtichkaEL [24]
I think it's true
I'm not really sure
7 0
3 years ago
Which of the following is not true about tectonic plates
AlladinOne [14]

Answer:

Scientists have identified about a dozen major and several minor tectonic plates

6 0
2 years ago
a car advertisement states that a certain car can accelerate from rest to 70km/h in 7 seconds. find the cars acceleration
ELEN [110]
<span>a = (v2 - v1)/t= acceleration formula

a = (70 - 0)/7
a = 10 km/hr/sec
-----
It's better to use as few units as possible.
10 km/hr = 10 km*1000 m/km/(1 hr*3600 sec/hr) = 25/9 m/sec
a= 25/9 m/sec/se</span>
4 0
3 years ago
Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and ex
Ahat [919]

The question is incomplete. The complete question is :

Two loudspeakers are placed 1.8 m apart. They play tones of equal frequency. If you stand 3.0 m in front of the speakers, and exactly between them, you hear a minimum of intensity. As you walk parallel to the plane of the speakers, staying 3.0 m away, the sound intensity increases until reaching a maximum when you are directly in front of one of the speakers. The speed of sound in the room is 340 m/s.

What is the frequency of the sound?

Solution :

Given :

The distance between the two loud speakers, d = 1.8 \ m

The speaker are in phase and so the path difference is zero constructive interference occurs.

At the point D, the speakers are out of phase and so the path difference is $=\frac{\lambda}{2}$

Therefore,

$AD-BD = \frac{\lambda}{2}

$\sqrt{(1.8)^2+(3)^2-3} =\frac{\lambda}{2}$

$\lambda = 2 \times 0.4985$

$\lambda = 0.99714 \ m$

Thus the frequency is :

$f=\frac{v}{\lambda}$

$f=\frac{340}{0.99714}$

f=340.9744 Hz

3 0
2 years ago
An egg is dropped from the top of the band hall. if the band hall is 25 m tall, determine the time it takes the egg to hit the f
Vera_Pavlovna [14]

Answer:

2.26 s

Explanation:

The following data were obtained from the question:

Height (h) = 25 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =..?

The time taken for the egg to hit the floor can be obtained as illustrated below:

h = ½gt²

25 = ½ × 9.8 × t²

25 = 4.9 × t²

Divide both side by 4.9

t² = 25 / 4.9

Take the square root of both side

t = √(25 / 4.9)

t = 2.26 s

Thus, it will take 2.26 s for the egg to hit the floor.

7 0
3 years ago
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