The crest of the wave has traveled 415 cm in 11.7s. then the crest should have travelled 415/11.7 cm in one second i.e. 35.47cm. Then the crest should have travelled 26*35.47 cm in 26 seconds i.e. 922.2cm which has 46 vibrations in it.
so for length of each vibration (Wavelength) is 20 cm
Answer:
Given that
m = 5.3 kg
Fx = 2x + 4
We know that work done by force F given as
w= ∫ F. dx
a)
Given that x=1.08 m to x=6.5 m
Fx = 2x + 4
w= ∫ F. dx

![w=\left [x^2+4x \right ]_{1.08}^{6.5}](https://tex.z-dn.net/?f=w%3D%5Cleft%20%5Bx%5E2%2B4x%20%5Cright%20%5D_%7B1.08%7D%5E%7B6.5%7D)

w=62.7 J
b)
We know that potential energy given as

∫ dU = -∫F.dx ( w= ∫ F. dx)
ΔU= -62.7 J
c)
We know that form work power energy theorem
Net work = Change in kinetic energy
W= KE₂ - KE₁
62.7 =KE₂ - (1/2)x 5.3 x 3²
KE₂ = 86.55 J
This is the kinetic energy at 6.5m
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The answer should be flammability
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