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Elanso [62]
3 years ago
8

How much smaller is an electron than a proton​

Chemistry
2 answers:
Gwar [14]3 years ago
8 0

Answer: A proton is about a billion times more massive than an electron.  They are smaller than we can currently measure and may not have a size at all!

Explanation:

meriva3 years ago
3 0

Answer:

An electron is around 1800 times smaller than a proton

Explanation:

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Which of the changes gas to solid gas to liquid, liquid to solid liquid to gas,solid to liquid solid to gas will involve an outp
Verdich [7]

Answer:

Liquid to solid liquid to gas

Explanation:

Boiling a liquid result in a gas

7 0
2 years ago
Calculate the mass of bromine in 50.0 g of potassium bromide
Elodia [21]

Answer:

6 Percent Composition. 1. Molar Mass of KBr K = 1(39.10) = 39.10 Br =1(79.90) =79.90 MM = 119.0 79.90 g        119.0 g = 0.6714 3. 0.6714 x 50.0g = 33.6 g Br 2.

4 0
2 years ago
Despite the fact that the partial pressure difference is so much smaller for co2, why is there as much co2 exchanged between the
Snezhnost [94]
This is due to the solubility of CO₂ in blood is more than the solubility of Oxygen in blood 
7 0
3 years ago
In the investigation "Comparing the Effects of the Products of Cellular Respiration
Marianna [84]

The solution changed color because the substances are not neutral.

<h3>pH</h3>

Chemical substances have different concentrations of the hydrogen cation, called PH.

The higher the pH, the more basic the substance, and the lower the more acidic.

Bromothymol blue is a pH indicator that changes its color according to the pH of the substance, yellow for acid, blue for basic and green for neutral.

In the case of the reactions in question, we have the release of CO2 (acid) in combustion and in cellular respiration, changing the color of bromothymol blue to yellow.

Learn more about pH in: brainly.com/question/491373

3 0
2 years ago
What are the equilibrium concentrations of pb2+ and f– in a saturated solution of lead(ii) fluoride if the ksp of pbf2 is 3.20×1
erica [24]
Answer is:  the equilibrium concentrations fluorine anion are 0.004 M and lead cation are 0.002 M.<span>
Chemical reaction: PbF</span>₂(aq) → Pb²⁺(aq) + 2F⁻(aq).<span>
Ksp = 3,2·10</span>⁻⁸.
[Pb²⁺] = x.
[F⁻] = 2[Pb²⁺] = 2x<span>
Ksp = [Pb²</span>⁺] · [F⁻]².
Ksp = x · 4x².
3,2·10⁻⁸ = 4x³.
x = ∛3,2·10⁻⁸ ÷ 4.
x = [Pb²⁺] = 0,002M = 2·10⁻³ M.
[F⁻] = 2 · 0,002M = 0,004 M = 4·10⁻³ M.

6 0
3 years ago
Read 2 more answers
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