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Rama09 [41]
3 years ago
9

Choose the correct statement for this question: If two objects have different temperatures, in which direction will heat move? F

or how long?
1. Heat moves from hot to cold objects/areas, and it never stops.
2. Heat moves from cold to hot object/areas.
3.Heat moves from hot objects/areas to cold areas and stops moving once it reaches a thermal equilibrium.
Chemistry
1 answer:
Gekata [30.6K]3 years ago
8 0
I would go with the first one
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3 years ago
What is the solubility of iron in water at 25 degrees Celsius
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Fe(No3)2 because Fe(No3)2 is soluble
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Help!!<br> Classify each diagram as an element a compound or mixture
Black_prince [1.1K]

Answer:

1. Mixture

2. Compound

3. Compound

4. Element

Explanation:

Number 1 shows two completely different types of compounds in the same space, so it is a mixture.

Numbers 2 and 3 are compounds because there aren't different types compounds as in Number 1, but the same compound repeated. 2 is a compound because while all of the circles are the same element, they are connected. O2 for example, oxygen, is a compound.

Number 4, finally, is all of the same substance, non-connected, so it shows an element.

Brainliest, please :) (Trying to become a genius so that I can continue helping more people)

8 0
2 years ago
The element europium exists in nature as two isotopes: has a mass of u and has a mass of u. The average atomic mass of europium
ElenaW [278]

Answer:

Problem Details

The element europium exists in nature as two isotopes:  151Eu has a mass of 150.9196 amu, and 153Eu has a mass of 152.9209 amu. The average atomic mass of europium is 151.96 amu. Calculate the relative abundance of the two europium isotopes.

answer:

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4 0
3 years ago
When of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing poi
Nesterboy [21]

The given question is incomplete. The complete question is:

When 282. g of glycine (C2H5NO2) are dissolved in 950. g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 282. g of ammonium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for ammonium chloride in X.

Answer:  the van't Hoff factor for ammonium chloride is 1.74

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point  

K_f = freezing point constant = ?

i = 1 ( for non electrolyte)

m= molality

8.2^0C=1\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of solute (glycine) = 75.07 g/mol

Mass of solute (glycine) = 282 g

8.2^0C=1\times K_f\times \frac{282g}{75.07g/mol\times 0.95kg}

K_f=2.07

ii) 20.0^0C=i\times \times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of solute (ammonium chloride) = 53.49 g/mol

Mass of solute (ammonium chloride) = 282 g

20.0^0C=i\times 2.07\times \frac{282g}{53.49g/mol\times 0.95kg}

i=1.74

Thus the van't Hoff factor for ammonium chloride is 1.74

4 0
3 years ago
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