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andrew-mc [135]
3 years ago
11

A sample of 25.0 mL of 0.120 M Ca(OH)2(aq) is titrated with 0.150 M HCl(aq). What volume of HCl(aq) is needed to completely neut

ralize the Ca(OH)2(aq)
Chemistry
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

V_{HCl}=48.0 mL

Explanation:

Hello!

In this case, since the reaction between calcium hydroxide and hydrochloric acid shows a 2:1 mole ratio between them:

2HCl+Ca(OH)_2\rightarrow CaCl_2+2H_2O

We need to use the following mole ratio:

2n_{Ca(OH)_2}=n_{HCl}

That can be written in volumes and concentrations:

2M_{Ca(OH)_2}V_{Ca(OH)_2}=M_{HCl}V_{HCl}

Thus, we solve for the volume of HCl as it is the unknown:

V_{HCl}=\frac{2M_{Ca(OH)_2}V_{Ca(OH)_2}}{M_{HCl}}

Therefore, we plug in to obtain:

V_{HCl}=\frac{2*0.120M*25.0mL}{0.150M} \\\\V_{HCl}=48.0 mL

Best regards!

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Find the percent composition of C7H5N3O6
Oksana_A [137]

Finding percent composition is fairly easy. You only need to divide the mass of an element by the total mass of the compound. We can do this one element at a time.

First, let's find the total mass by using the masses of the elements given on the periodic table.

7 x 12.011 (mass of Carbon) = 84.077

5 x 1.008 (mass of Hydrogen) = 5.04

3 x 14.007 (mass of Nitrogen) = 42.021

6 x 15.999 (mass of Oxygen) = 95.994

Add all of those pieces together.

84.077 + 5.04 + 42.021 + 95.994 = 227.132 g/mol is your total. Since we also just found the mass of each individual element, the next step will be very easy.

Carbon: 84.077 / 227.132 = 0.37016 ≈ 37.01 %

Hydrogen: 5.04 / 227.132 = 0.022189 ≈ 2.22 %

Nitrogen: 42.021 / 227.132 = 0.185 ≈ 18.5 %

Oxygen: 95.994 / 227.132 = 0.42263 ≈ 42.26 %

You can check your work by making sure they add up to 100%. The ones I just found add up to 99.99, which is close enough. A small difference (no more than 0.03 in my experience) is just a matter of where you rounded your numbers.

5 0
3 years ago
Nitric oxide (NO) is a gaseous molecule with lipid solu- bility similar to that of O2 and CO2. Endothelial cells lining arteries
svp [43]

Answer:

NO passively diffuses down its concentration gradient through the endothelial cell plasma membrane out of the cell and then passiveley diffuses through the plasma membrane into the cytoplasm of the smooth muscle cell, where it acts to decrease contraction.

Explanation:

Hello,

At first, we must consider that O_2 and CO_2, NO passively diffuses through membranes. As it is produced by an enzyme and accumulates in the endothelial cell cytosol, NO passively diffuses down its concentration gradient through the endothelial cell plasma membrane out of the cell and then passiveley diffuses through the plasma membrane into the cytoplasm of the smooth muscle cell, where it acts to decrease contraction.

Best regards

5 0
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4vir4ik [10]

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The most common sample of EM waves in telecommunication is radio, light and infra-red signals. An example of a mechanical wave is a sound wave, which requires air to travel. Oscillating molecules made the sound waves. 

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Answer:

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