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Blababa [14]
3 years ago
6

Please help me, theres more than 1 pictures btw

Physics
2 answers:
dexar [7]3 years ago
6 0
1-c 2-d 3-p 4-a 5-c 6-d 7-t 8-d ~i’m in 8th grade and just finished this stuff soo ik i’m right.~
Alla [95]3 years ago
3 0

Answer:

1.D   2.Infaret light waves the bottom answer is Wavelength and frequency are two such characteristics. The relationship between wavelength and frequency is that the frequency of a wave multiplied by its wavelength gives the speed of the wave, as we will see below. That's all I know. Hopwfully it helps.

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I am an animal named after the animal that I eat, what am I?
Gnom [1K]

the answer is an anteater

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4 years ago
What is the dimensional formula of thermal conductivity?​
Inga [223]

Answer:

The dimension of thermal conductivity is M1L1T−3Θ−1, expressed in terms of the dimensions mass (M), length (L), time (T), and temperature (Θ). Other units which are closely related to the thermal conductivity are in common use in the construction and textile industries.

Explanation:looked it up for ya

6 0
3 years ago
Two forces act on a 6.00-kg object. One of the forces is 10.0 N. If the object accelerates at 2.00 m/s2
liubo4ka [24]

Given :

Two forces act on a 6.00-kg object. One of the forces is 10.0 N.

Acceleration of object 2 m/s².

To Find :

The greatest possible magnitude of the other force.\

Solution :

Let, other force is f.

So, net force, F = 10 + f.

Now, acceleration is given by :

a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N

Therefore, the greatest possible magnitude of the other force is 2 N.

Hence, this is the required solution.

7 0
3 years ago
Marble and cotton ball friction assignment
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8 0
3 years ago
Stewart (70 Kg) is attracted to Ms. Little (60 Kg) who sits 2 m away. What is the gravitational attraction between them? G=6.67×
ikadub [295]

Happy Holidays!

We can use the following equation to solve for the gravitational force:

\large\boxed{F_g = G\frac{m_1m_2}{r^2}}

Fg = force due to gravity (N)

G = Gravitational constant

m1,m2 = masses of the objects (kg)

r = distance between the objects (m)

Plug in the given values into the equation:

F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}

7 0
3 years ago
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