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Blababa [14]
3 years ago
6

Please help me, theres more than 1 pictures btw

Physics
2 answers:
dexar [7]3 years ago
6 0
1-c 2-d 3-p 4-a 5-c 6-d 7-t 8-d ~i’m in 8th grade and just finished this stuff soo ik i’m right.~
Alla [95]3 years ago
3 0

Answer:

1.D   2.Infaret light waves the bottom answer is Wavelength and frequency are two such characteristics. The relationship between wavelength and frequency is that the frequency of a wave multiplied by its wavelength gives the speed of the wave, as we will see below. That's all I know. Hopwfully it helps.

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Find B when θ=35, E=10V, t=5, N=250, A=1.20m^2
givi [52]

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Explanation:

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3 years ago
If earth stops rotating then what will be the value of 'g' at poles
Marianna [84]
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3 years ago
When light of wavelength 240 nm falls on a cobalt surface, electrons having a maximum kinetic energy of 0.17 eV are emitted. Fin
dusya [7]

Answer:

(a) 5.04 eV (B) 248.14 nm (c) 1.21\times 10^{15}Hz

Explanation:

We have given Wavelength of the light  \lambda = 240 nm

According to plank's rule ,energy of light

E = h\nu = \frac{hc}{}\lambda

E = h\nu = \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{ 240\times 10^{-9} m\times 1.6\times 10^{-19}J/eV}= 5.21 eV

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Part( A) Using Einstien's equation

E = KE_{max}+\Phi _{0}, here \Phi _0 is work function.

\Phi _{0}=E - KE_{max}= 5.21 eV-0.17 eV = 5.04 eV

Part( B) We have to find cutoff wavelength

\Phi _{0} = \frac{hc}{\lambda_{cuttoff}}

\lambda_{cuttoff}= \frac{hc}{\Phi _{0} }

\lambda_{cuttoff}= \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{5.04 eV\times 1.6\times 10^{-19}J/eV }=248.14 nm

Part (C) In this part we have to find the cutoff frequency

\nu = \frac{c}{\lambda_{cuttoff}}= \frac{3\times 10^{8}m/s}{248.14 \times 10^{-19} m }= 1.21\times 10^{15} Hz

5 0
3 years ago
During a summer with little rainfall, your house on a hill slope experiences an interval during which your well runs dry. You ha
irina1246 [14]

Answer and Explanation:

You don't have water because of two possible reasons:

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