nabr + cacl2 are the products
The excess reactant when 4.35 g of hydrogen reacts with 30.75g of hydrogen iodide is hydrogen
<h3>calculation</h3>
write the equation for the reaction
H2(g) + I2 (g) → 2HI (g)
find the mole of each reactant
moles = mass/molar mass
moles of H2= 4.35 g/2 g/mol= 2.175 moles
moles o I2 = 30.75 g/ 254 g/mo=0.1211 moles
0.1211 moles of I2 reacted with 0.1211 moles of H2 but there are more moles of H2 there Hydrogen was in excess
When water (H2O) is added to liquid isopropanol to form a solution, then polar isopropanol molecules are attracted to polar water molecules at the surface of the water. It forms a solution of rubbing alcohol.
<h3>Isopropanol and water in the solution</h3>
Isopropyl alcohol is water-soluble and forms hydrogen bonds with molecules of water (H2O).
When H2O is added to liquid isopropanol to form a solution, H2O spread in a uniform way in the solution.
These isopropanol molecules can surround H2O molecules, which are carried into the solution.
Learn more about isopropyl alcohol here:
brainly.com/question/799124