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AVprozaik [17]
3 years ago
13

Exercise 2: (7 points)

Chemistry
1 answer:
Marat540 [252]3 years ago
4 0

Answer:

See explanation

Explanation:

I) from the question;

500 × 10^-3 g dissolves in 100ml

xg dissolves in 1000ml

x = 500 × 10^-3 g × 1000ml/100 ml

x= 5 g/L

Mass concentration = molar concentration × molar mass

Molar concentration = Mass concentration/ molar mass

Molar concentration = 5g/L/419 g/mol

Molar concentration = 0.0119 M

ii) To prepare this solution, measure out 500mg with a weighing balance. Transfer the solid to a standard 100 ml volumetric flask. Make up to the 100ml mark with distilled water.

iii) mass concentration of the solution = 50 g/L

Volume of the solution= 100 ml

Mass of the solid = 50 g/L × 100/1000 L

Mass of solid = 5g

This 5g was taken for 10 days, hence a total of 50 g

Since the normal dose of the drug is 40g for ten days, the patient will suffer from kidney problems because he/she has taken the drug above the recommended dosage.

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We can use the<em> Ideal Gas Law </em>to solve this problem.

pV = nRT     Divide both sides by RT

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(c) <em>Calculate the number of moles </em>

n = (0.8500 × 25.0)/(0.082 06 × 295.15)

  = 0.877 mol

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