Answer:
D. 15.8atm
Explanation:
Given parameters:
Initial pressure = 13atm
Initial temperature = 34°C = 34 + 273 = 307K
Final temperature = 100°C = 100 + 273 = 373K
Unknown:
Final pressure = ?
Solution:
To solve this problem, we apply a derivation of the combined gas law taking the volume as a constant.
The expression is shown mathematically below;
= 
P and T pressure and temperature values
1 and 2 are initial and final states
Insert the parameters and solve for T₂;
= 
P₂ = 15.8atm
Answer:
0.116 grams
We can use King Henry Died Unusually Drinking Chocolate Milk
The partial pressure of Hydrogen gas can directly be calculated
by simply taking the difference of the overall pressure and the vapour pressure
of water. That is:
P (H2 gas) = 759.2 torr – 23.8 torr
<span>P (H2 gas) = 735.4 torr</span>
Answer: 39.948 grams
Explanation:
The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Ar, or 39.948 grams
Answer:
Mole fraction of solute is 0.0462
Explanation:
To solve this we use the colligative property of lowering vapor pressure.
First of all, we search for vapor pressure of pure water at 25°C = 23.8 Torr
Now, we convert the Torr to mmHg. Ratio is 1:1, so 23.8 Torr is 23.8 mmHg.
Formula for lowering vapor pressure is:
ΔP = P° . Xm
Where ΔP = P' (Vapor pressure of solution) - P° (Vapor pressure of pure solvent)
Xm = mole fraction
24.9 mmHg - 23.8 mmHg = 23mmHg . Xm
Xm = (24.9 mmHg - 23.8 mmHg) / 23mmHg
Xm = 0.0462
