Answer:
θ₁ = 35.32°
Explanation:
given,
refractive index of medium 1 = n₁ = 1.75
refractive index of medium 2 = n₂ = 1.24
condition to describe the refracted angle
...(1)
Using Snell's Law
n₁ sin θ₁ = n₂ sin θ₂
θ₁ , θ₂ is the angle of incidence and refractive index
n₁. n₂ is the refractive index medium 1 and medium 2
1.75 x sin θ₁ = 1.24 x sin θ₂
From equation (1)
1.75 x sin θ₁ = 1.24 x sin (90-θ₁)
1.75 sin θ₁ = 1.24 cos θ₁
tan θ₁ = 0.708
θ₁ = 35.32°
Hence, angle of incidence is equal to θ₁ = 35.32°
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Answer:
Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.
Explanation:
Given that
Yield strength ,Sy= 240 MPa
Tensile strength = 310 MPa
Elastic modulus ,E= 110 GPa
L=380 mm
ΔL = 1.9 mm
Lets find strain:
Case 1 :
Strain due to elongation (testing)
ε = ΔL/L
ε = 1.9/380
ε = 0.005
Case 2 :
Strain due to yielding
ε '=0.0021
Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.
For computation of load strain due to testing should be less than the strain due to yielding.
Answer:
Explanation:
Pressure due to fluid is directly proportional to the depth of fluid, density of the fluid and the value of acceleration due to gravity.
P = h d g
Where, h is the depth, d be the density and g be the acceleration due to gravity.
If we talk about teh atmospheric pressure, the density of air goes on decreasing as we go up and up. o we cannot say that it is directly depends only on the depth of air, it also depends on the changing density of air.
Answer:
ε = 6.617 V
Explanation:
We are given;
Number of turns; N = 40 turns
Diameter;D = 18cm = 0.18m
magnetic field; B = 0.65 T
Time;t = 0.1 s
The formula for the induced electric field(E.M.F) is given by;
ε = |-NAB/t|
A is area
ε is induced electric field
While N,B and t remain as earlier described.
Area = π(d²/4) = π(0.18²/4) = 0.02545
Thus;
ε = |-40 × 0.02545 × 0.65/0.1|
ε = 6.617 V
(we ignore the negative sign because we have to take the absolute value)
