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Talja [164]
3 years ago
9

In the formation of sodium chloride by the combination of sodium and chlorine:

Chemistry
1 answer:
Ierofanga [76]3 years ago
7 0

Answer:

Na(s) + Cl2(g) = NaCl(s)

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MAVERICK [17]

Answer:

           

Explanation:

       

7 0
2 years ago
When an alkane reacts with an element from group 7a, the reaction is referred to as?
Elena-2011 [213]
Alkanes are saturated hydrocarbon, that is they contain hydrogen and carbon without a double or triple bond between the carbon atoms, e.g. ethane, propane. Group 7a in the periodic table are called halogens e.g chlorine, bromine. Alkanes react with halogens in a reaction called substitution, where halogens replace hydrogen atoms in alkanes.
7 0
3 years ago
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What is a tolerant of sea spray? I NEED HELP WITH THIS QUESTION !!! Answer fast for 20 poins
DedPeter [7]

Answer:

American Holly, Black Pine, Blue Pacific Juniper, Blue Dune Grass, Artemesia) MODERATELY SALT TOLERANT: plants always need protection from salt spray but will tolerate some inundations by storm surges. They are best used behind fences or buildings. (

3 0
2 years ago
Calculate the entropy change for the surroundings of the reaction below at 350K: N2(g) + 3H2(g) -> 2NH3(g) Entropy data: NH3
krek1111 [17]

Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K

Explanation :

We have to calculate the entropy change of reaction (\Delta S^o).

\Delta S^o=S_{product}-S_{reactant}

\Delta S^o=[n_{NH_3}\times \Delta S^0_{(NH_3)}]-[n_{N_2}\times \Delta S^0_{(N_2)}+n_{H_2}\times \Delta S^0_{(H_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S^0{(NH_3)} = standard entropy of NH_3

\Delta S^0{(H_2)} = standard entropy of H_2

\Delta S^0{(N_2)} = standard entropy of N_2

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (192.5J/K.mole)]-[1mole\times (191.5J/K.mole)+3mole\times (130.6J/K.mole)]

\Delta S^o=-198.3J/K

Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K

4 0
2 years ago
Need a bit of help with this. Fill in the coefficients, explain your answer.
sp2606 [1]

Answer:

4Fe + 3O₂ → 2Fe₂O₃

General Formulas and Concepts:

<u>Chemistry - Reactions</u>

  • Balancing Reactions

Explanation:

<u>Step 1: Define</u>

RxN:   Fe + O₂ → Fe₂O₃

<u>Step 2: Balance</u>

We need to balance both Fe and O.

LCM of 2 and 3 is 6:

Fe + 3O₂ → 2Fe₂O₃

We now need the same amount of Fe on both sides:

4Fe + 3O₂ → 2Fe₂O₃

4 0
3 years ago
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