Answer:
After power is generated at a power plant, its voltage is increased by a step-up transformer. The power then travels through transmission lines to a neighborhood where it will run homes, offices, and factories. But before entering the neighborhood, the power's voltage is decreased by a step-down transformer
Transformers can be used either to increase the voltage (called "stepping up") or decrease the voltage ("step down"). When electrical energy travels long distances in wires, some of the energy is lost. ... Later, the voltage is stepped down before it enters your home - once again using transformers
5.5 s
Explanation:
The time it takes for the ball to reach its maximum height can be calculated using
since 
at the top of its trajectory. Plugging in the numbers,
Answer:
τ ≈ 0.90 N•m
F =
Explanation:
I = ½mR² = ½(10)0.5² = 1.25 kg•m²
α = ω²/2θ = 3.0² / 4π = 0.716... rad/s²
τ = Iα = 1.25(0.716) = 0.8952... ≈ 0.90 N•m
τ = FR
Now we have the unanswered question of reference frame.
80° from what?
If it's 80° from the radial
F = τ/Rsinθ = 0.90/0.5sin80 = 1.818... ≈ 1.8 N
If it's If it's 80° from the tangential
F = τ/Rcosθ = 0.90/0.5cos80 = 10.311... ≈ 10 N
There are an infinite number of other potential solutions
Answer:
-54 m/s²
Explanation:
Acceleration is defined as the change in velocity of a body with respect to time. Mathematically,
Acceleration A = change in velocity/time
A = dv/dt
Given Vx = at − bt³
The time at which the particle reaches its maximum displacement is at when vx = 0.
0 = at-bt³
t(a-bt²) = 0
a-bt² = 0
a = bt²
t² = a/b ... (1)
A = dvx/dt = a - 3bt²(by differentiating)
Acceleration = a - 3bt²... (2)
Substituting t² = a/b into equation 2 will give;
Acceleration = a - 3b(a/b)
Acceleration = a-3a
Acceleration = -2a
Substituting the value of a = 27m/s into the resulting equation of acceleration gives;
Acceleration = -2(27)
Acceleration = -54m/s²
Therefore at maximum displacement in the positive x direction, the acceleration of the particle will be -54m/s²
