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STALIN [3.7K]
2 years ago
11

What is the force of repulsion between two points positive charges 5 and 8 separated at a distance of 0.02m apart

Physics
1 answer:
Zinaida [17]2 years ago
4 0

Explanation:

F =(frac{1}{4{pi}{varepsilon}_o}) x (frac {q_1q_2}{r^2})

F =(frac {5 {times} 10 {times} 8 {times} 10}{0.002 {times} 0.002}) x 9 x 10

F = 900N

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A uniform electric field exists everywhere in the x, y plane. This electric field has a magnitude of 4500 N/C and is directed in
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Answer with Explanation:

We are given that

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E'=\frac{Kq}{r^2}=\frac{9\times 10^9\times 5.5\times 10^{-9}}{(0.2)^2}=1237.5 N

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