Question

What is the force of repulsion between two points positive charges 5 and 8 separated at a distance of 0.02m apart

Answer 1

Explanation:

F =(frac{1}{4{pi}{varepsilon}_o}) x (frac {q_1q_2}{r^2})

F =(frac {5 {times} 10 {times} 8 {times} 10}{0.002 {times} 0.002}) x 9 x 10

F = 900N