Question

TIMED HELP PLSPLS ASAP UNDER 5 MIN REMAINING

Answer 1

Answer:

3.98×10⁻¹⁹ J

Explanation:

Applying,

E = hf................. Equation 1

Where E = energy of the photon, h = planck's constant, f = frequency of the photon

From the question,

Given: f = 6.00×10¹⁴ Hz

Constant: h = 6.626×10⁻³⁴J.s

Substitute these values into equation 1

E = (6.00×10¹⁴)(6.626×10⁻³⁴)

E = 39.756×10⁻²⁰

E = 3.98×10⁻¹⁹ J

Hence the energy of the photon in joules is 3.98×10⁻¹⁹ J