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3 years ago

More advanced line dances, that requires more intense steps, can be considered

Physics

1 answer:

garri49 [273]3 years ago

3 0

Answer:

Vigorous activity

Explanation:

Vigorous activity

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A beam of unpolarized light in air strikes a flat piece of glass at an angle of incidence of 54.2 degrees. If the reflected beam

Stels [109]

Answer:

correct option is B. 1.39

Explanation:

given data

angle of incidence (θ) = 54.2 degrees

to find out

index of refraction of the glass

solution

we know that here reflected beam is completely polarized

so angle of incidence = angle of polarized ....................1

for reflective index we apply here Brewster law that is

μ = tan(θ) ...............2

put here θ value we get

μ = tan(54.2)

μ = 1.386

so correct option is B. 1.39

6 0

3 years ago

Read 2 more answers

A proton is traveling horizontally to the right at 1.8 × 106 m/s. (a) Find the magnitude and direction of the weakest electric f

Mars2501 [29]

Answer:

528398.4375 N/C opposite to the direction of the proton

$3.56\times 10^{-8}\ s$

288.24609375 N/C in the same direction of the motion of the electron

Explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity = $1.8\times 10^{6}\ m/s$

s = Displacement = 3.2 cm

a = Acceleration

Mass of electron = $9.11\times 10^{-31}\ kg$

Mass of electron = $1.67\times 10^{-27}\ kg$

q = Charge of particle = $1.6\times 10^{-19}\ C$

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-(1.8\times 10^6)^2}{2\times 0.032}\\\Rightarrow a=-5.0625\times 10^{13}\ m/s^2$

Electric field is given by

$E=\dfrac{ma}{q}\\\Rightarrow E=\dfrac{1.67\times 10^{-27}\times -5.0625\times 10^{13}}{1.6\times 10^{-19}}\\\Rightarrow E=−528398.4375\ N/C$

The electric field is 528398.4375 N/C opposite to the direction of the proton

$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-1.8\times 10^6}{-5.0625\times 10^{13}}\\\Rightarrow t=3.56\times 10^{-8}\ s$

The time taken is $3.56\times 10^{-8}\ s$

$E=\dfrac{ma}{q}\\\Rightarrow E=\dfrac{9.11\times 10^{-31}\times -5.0625\times 10^{13}}{-1.6\times 10^{-19}}\\\Rightarrow E=288.24609375\ N/C$

The electric field is 288.24609375 N/C in the same direction of the motion of the electron

7 0

4 years ago

Kamila [148]

Answer: (x - 4)² + (y - 7)² = 9

<u>Explanation:</u>

The equation of a circle is: (x - h)² + (y - k)² = r² where

(h, k) is the center
r is the radius

Given: (h, k) = (4, 7)

Find the intersection of the given equation and the perpendicular passing through (4, 7).

3x - 4y = -1

-4y = -3x - 1

$y=\dfrac{3}{4}x-1$

$m=\dfrac{3}{4}$ --> $m_{\perp}=-\dfrac{4}{3}$

$y-y_1=m_{\perp}(x-x_1)\\\\y-7=-\dfrac{4}{3}(x-4)\\\\\\y=-\dfrac{4}{3}x+\dfrac{16}{3}+7\\\\\\y=-\dfrac{4}{3}x+\dfrac{37}{3}$

Use substitution to find the point of intersection:

$x=\dfrac{29}{5}=5.8,\qquad y=\dfrac{23}{5}=4.6$

Use the distance formula to find the distance from (4, 7) to (5.8, 4.6) = radius

$r=\sqrt{(5.8-4)^2+(4.6-7)^2}\\\\r=\sqrt{3.24+5.76}\\\\r=\sqrt9\\\\r=3$

Input h = 4, k = 7, and r = 3 into the circle equation:

(x - 4)² + (y - 7)² = 3²

(x - 4)² + (y - 7)² = 9

4 0

3 years ago

Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be a

Helen [10]

Complete Question

Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be added to the gas in the form of heat by applying a flame to the outside of the container. Conversely, energy can also be removed from the gas in the form of heat by immersing the container in ice water. Energy can be added to the system in the form of work by pushing the piston in, thereby compressing the gas. Conversely, if the gas pushes the piston out, thereby pushing some atmosphere aside, the internal energy of the gas is reduced by the amount of work done.

$pV=nRT$

so the absolute temperature T is directly proportional to the product of the absolute pressure p and the volume V,Here n denotes the amount of gas moles,which is a constant because the gas is confined and R is the universal constant

What is the $\triangle U$ as the system of ideal gas goes from point A to point B on the graph recall u is proportional to T

Answer:

$\triangle T=0$

$\triangle V=0$

The gas A and B have same internal energy

Explanation:

From the question we are told that

$Pa=u atm\\Va=1m^3\\Pb=1 atm\\Vb=4m^3$

Generally the equation of temperature is mathematically given as

$Ta=\frac{Pv}{nR}$

$Ta=\frac{u*1}{nR}$

And

$Tb=\frac{PbVb}{nR}$

$Tb=\frac{u*1}{nR}$

Generally the change in temperature $\triangle T$ is mathematically given as

$\triangle T=Tb-Ta=Tb=\frac{u*1}{nR}-\frac{u*1}{nR}$

$\triangle T=0$

Generally the change in internal energy $\triangle V$

$\triangle V=nC_v \triangle T\\$

$\triangle V=0$

Therefore with

$\triangle T=0$

$\triangle v=0$

The gas A and B have same internal energy

6 0

3 years ago

The efficiency of a carnot cycle is 1/6. If on reducing the temperature of the sink 75 degree Celsius, the efficiency becomes 1/

svp [43]

Answer:

375 and 450

Explanation:

The computation of the initial and the final temperature is shown below:

In condition 1:

The efficiency of a Carnot cycle is $\frac{1}{6}$

So, the equation is

$\frac{1}{6} = 1 - \frac{T_2}{T_1}$

For condition 2:

Now if the temperature is reduced by 75 degrees So, the efficiency is $\frac{1}{3}$

Therefore the next equation is

$\frac{1}{3} = 1 - \frac{T_2 - 75}{T_1}$

Now solve both the equations

solve equations (1) and (2)

$2(1 - T_2/T_1) = 1 - (T_2 - 75)/T_1\\\\2 - 1 = 2T_2/T_1 - (T_2 - 75)/T_1\\\\ = (T_2 + 75)/T_1T_1 = T_2 + 75\\\Now\ we\ will\ Put\ the\ values\ into\ equation (1)\\\\1/6 = 1 - T_2/(T_2 + 75)\\\\1/6 = (75)/(T_2 + 75)$

T_2 + 450 = 75

T_2 = 375

Now put the T_2 value in any of the above equation

i.e

T_1 = T_2 + 75

T_1 = 375 + 75

= 450

7 0

3 years ago