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Lelechka [254]
3 years ago
11

The rate constant for a particular second order reaction is 2.4 x 10-2 M-1 s-1 at 35∘C. If the initial concentration of the reac

tant is 1.20 M, what is the concentration (in M) after 4 minutes?
Chemistry
1 answer:
Andrews [41]3 years ago
7 0

Answer:

C_2=0.21M

Explanation:

From the question we are told that:

Rate constant K=2.4 x*10^{-2} M-1 s-1

Temperature T=35^o

Initial concentration C_1=1.20M

Time T=4min=>240sec

Generally the equation for  second order reacion is mathematically given by

\frac{1}{C_2} = \frac{1}{C_1} +Kt

\frac{1}{C_2} = \frac{1}{1.2 } +2.4 * 10^{-2} *240

\frac{1}{C_2} = 4.8

C_2=0.21M

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