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3 years ago

Billy stands on a hill without slipping. In which direction is the force of friction acting?

Physics

2 answers:

EleoNora [17]3 years ago

4 0

D. Along the surface of the hill toward the top of the hill.

baherus [9]3 years ago

3 0

Answer: D. Along the surface of the hill toward the top of the hill.

Hope I helped you!

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PLEASE ANSWER! WILL MARK BRAINLIEST!

KatRina [158]

The answer is a Mid-Ocean ridge.

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4 years ago

Read 2 more answers

A car has a distance between axles of 6.2 m and a center of mass located 2.2 m from the front axle. What is the

NARA [144]

Answer:

The correct option is C

Explanation:

From the question we are told that

The distance between axles of the car is $d_a = 6.2$

The position of the car's center of mass is $D = 2.2 \ m \ in \ front \ of \ the \ axel$

Now we can evaluate the distance of the center of mass to the rear axle as follows

$k = d_a - D$

substituting values

$k = 6.2 - 2.2$

$k = 4 \ m$

assuming the car is at equilibrium, taking moment about the center of mass

$W_{front \ axle} * D - W_{rear \ axle} * k = 0$

=> $W_{front \ axle} * D = W_{rear \ axle} * k$

=> $\frac{W_{front \ axle}}{W_{rear \ axle} } = \frac{k}{D}$

substituting values

$\frac{W_{front \ axle}}{W_{rear \ axle} } = \frac{4}{2.2}$

$\frac{W_{front \ axle}}{W_{rear \ axle} } = 1.81$ Note [ $W_{front \ axle}$ is the front axle weight and

$W_{rear \ axle}$ is the rear axle weight ]

6 0

3 years ago

A horse pulls out 6000 J of work traveling 300 m . what is the force used ?

ziro4ka [17]

Energy is force * distance.

So force is energy/distance so 6000J/300m = 20N

4 0

3 years ago

A newly discovered planet has the same mass as the Earth, but a person standing on the surface of the planet experiences a force

Dafna11 [192]

This question deals with the acceleration due to gravity on the surface of the planet. The value of the acceleration due to gravity on the surface of two planets, that is Earth and on the surface of another planet are compared to find out the relation between the radii of both planets, provided their masses are the same.

The correct option for the radius of the new planet is "Option 3: Square Root of 3 R"

The value of the acceleration due to gravity on the surface of a planet is given by the following formula:

$g = \frac{GM}{R^2}$ ----------- eqn(1)

where,

g = acceleration due to gravity on Earth

G = Universal Gravitational Constant

M = mass of the Earth

R = Radius of the Earth

Now, the same formula for the acceleration due to gravity on the surface of the other planet can be written as follows:

$g' = \frac{GM'}{R'}\\\\$ ------------- eqn(2)

where,

g' = acceleration due to gravity on the new planet

G = Universal Gravitational Constant

M' = mass of the new planet

R' = Radius of the new planet

According to the given condition, the new planet has the same mass as the Earth's mass but the acceleration due to gravity on the surface of the new planet is one-third of the acceleration due to gravity on the surface of Earth.

$M'=M\\\\g'=\frac{1}{3}g$