All categories

4 years ago

Find the frequency of the 4th harmonic waves on a violin string that is 48.0cm long with a mass of 0.300 grams

Physics

1 answer:

Jlenok [28]4 years ago

4 0

Answer:

The frequency of the 4th harmonic of the string is 481.13 Hz.

Explanation:

When a stretch string fixed at both ends is set into vibration, it produces its lowest sound of possible note called the fundamental frequency. Under certain conditions on the string, higher frequencies called harmonics or overtones can be produced.

The frequency of the forth harmonic is the third overtone of the string and can be determined by:

f = $\frac{2}{L}$ $\sqrt{\frac{T}{m} }$

Given that; L = 48.0 cm = 0.48 m,

m = 0.3 g = 0.0003 Kg,

T = 4.0 N,

f = $\frac{2}{0.48}$ $\sqrt{\frac{4}{0.0003} }$

f = 4.1667 × 115.4701

= 481.1252

f = 481.13 Hz

The frequency of the 4th harmonic of the string is 481.13 Hz.

You might be interested in

If a rock on a cliff starts with 3,000 J of GPE and 0 J of KE and ends with 0 J of GPE and 5,000 J of KE, what law of physics wo

alexgriva [62]

The law of physics that this scenario would violate is the law of conservation of energy.

<h3>What is the law of conservation of energy?</h3>

The law of conservation of energy states that energy possessed by an object or physical body can neither be created nor destroyed but can only be transformed from one form to another.

This ultimately implies that, the energy possessed by the rock at the beginning must be equal to the energy possessed by the rock at the end in accordance with the law of conservation of energy.

Read more on energy here: brainly.com/question/1242059

6 0

2 years ago

A positively charged insulating rod is brought close to an object that is suspended by a string. If the object is repelled away

Trava [24]

Answer

A) Positively charged two insulating rod are brought closed to an object they repel each other. It means the Object is positively charged. Because similar charge repel each other.

The correct answer is Option A.

B) we know force between to charges is calculated using Formula

$F = \dfrac{kQ_1Q_2}{r^2}$ .......(1)

form the given condition in the question

$F' = \dfrac{k\dfrac{Q_1}{4}\dfrac{Q_2}{4}}{(\dfrac{r}{2})^2}$

$F' = \dfrac{k\dfrac{Q_1}{4}\dfrac{Q_2}{4}}{(\dfrac{r^2}{4})}$

$F' = \dfrac{4}{16}\dfrac{kQ_1Q_2}{r^2}$

from equation (1)

$F' = \dfrac{F}{4}$

hence, the correct answer is Option C.

3 0

3 years ago

A bowling ball is launched off the top of a 240-foot tall building. The height of the bowling ball above the ground t seconds af

Vilka [71]

Answer:

V = (-32t +32) ft/s

The velocity of the bowling ball after t seconds is the time derivative of the position function s(t). To obtain the velocity from s(t) we simply differentiate s(t) with respect to t. That is

V = ds(t)/dt = -16×2t + 32×1 = -32t + 32.

When differentiating, you multiply the coefficient of each term in the equation with the power of the variable and then reduce the power by 1 just like above.

Explanation:

8 0

3 years ago

Volume of a cylinder with a diameter of 1.55 cm and a height of 1.34 cm

Bogdan [553]

Answer:

2.53 cm³

Explanation:

Volume of cylinder = πr²h; where h is the height and r is the radius and

π = 3.14 approx.

Volume = 3.14 * (1.55/2)² * 1.34 = 2.53 cm³

I divided 1.55 by 2 because we were given the diameter and not radius. Diameter = radius / 2

4 0

3 years ago

A grapefruit falls from a tree and hits the ground 0.76 s later.

Tomtit [17]

Answer:

2.8 m 7.4 m/s

Explanation:

write all the values then use the equations of motion to find the distance and speed. please see attached photo

7 0

4 years ago