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nataly862011 [7]
2 years ago
13

calculate the amount of heat needed to boil 119. g of benzene, beginning from a temperature of 5.9°C.​

Chemistry
2 answers:
Keith_Richards [23]2 years ago
5 0
Okie so I can see you at the church in the morning or in a second and I don’t have
givi [52]2 years ago
4 0
Whajsjsisisihsisaooaaoapalsk
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The first step of electrophilic aromatic substitution involves the formation of the arenium ion intermediate.
Anastaziya [24]

Answer:

True

Explanation:

Aromatic compounds undergo substitution rather than addition reactions because the aromatic structure is maintained.

Electrophilic aromatic substitution begins with attack of the electrophile on the aromatic ring to yield a delocalized intermediate called the arenium intermediate. Loss of hydrogen from this intermediate yields the final product.

4 0
3 years ago
What is the frequency of a red light with a wavelength of 6.98 x 10^-6
nevsk [136]

Answer:

frequency of light = 4.2\times 10^{-13}

Explanation:

we know that relation between frequency and wavelength of light is

frequency × wavelength = speed of light.

therefore frequency = \frac{c}{wavelength}

                                  = \frac{3\times 10^{8}}{6.98\times 10^{-6}}

                                  =4.2\times 10^{-13}

4 0
3 years ago
Which of the following natural disasters is least likely to occur in Maryland?
aleksandr82 [10.1K]

Answer:

blizzard because it is cold and rainy all the time.

Explanation:

6 0
3 years ago
PLEASE HELP
Ede4ka [16]

Answer:

Explanation:

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6 0
3 years ago
At the beginning of the shift at 7:00 am, a client has 650 ml of normal saline solution left in the intravenous bag, which is in
madreJ [45]

The 8 hour shift is from 7.00 am to 3.00 pm.<span>
<span>At the beginning, from 7.00 am to 9.30am (2.5 hrs.),<span> the client has normal saline which </span></span>is infusing at 125 ml/hr.
Hence amount of normal saline which was injected= 2.5 hrs. x 125 ml/hr.
                                                                                 = 312.5 ml
from 9.30am to 3.00 pm (5.5 hrs) lactated ringer solution, which is to infuse at 100 ml/hr was given. 
Hence amount of lactated ringer solution given = 5.5 hrs x 100 ml/hr
                                                                           = 550 ml
Total amount of IV solution given = normal saline + lactated ringer solution
                                                     = 312.5 ml + 550 ml
                                                     = 862.5 ml
<span>                                                     = 863 ml</span></span>

5 0
3 years ago
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