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2 years ago

calculate the amount of heat needed to boil 119. g of benzene, beginning from a temperature of 5.9°C.

Chemistry

2 answers:

Keith_Richards [23]2 years ago

5 0

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givi [52]2 years ago

4 0

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Ethanol can react with hydrochloric acid to form chloroethane and water. When sulfuric acid is added, the

kaheart [24]

Answer: 1.Sulfuric acid is a catalyst

2. Vanadium(v) oxide is a catalyst

6 0

2 years ago

A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm

Ulleksa [173]

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100$

$Percent error = \frac{0.1}{63.2}\times 100$

$Percent error = 0.00158\times 100$

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100$

$Percent error = \frac{0.2}{63.2}\times 100$

$Percent error = 0.00316\times 100$

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100$

$Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100$

$Percent error = \frac{(0.5)}{63.2}\times 100$

$Percent error = 0.00791\times 100$

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%

7 0

3 years ago

if I have 22.1 grams of CO2 gas at -188 degrees Celsius and 165 ml what is the pressure of the gas in kPa

Harman [31]

Answer:

P = 2.145kPa

Explanation:

Mass = 22.1g

Molar mass of CO2 = 44g/mol

Vol = 165mL = 0.165L

T = -188°C = (-188 + 273.15)K = 85.15K

R = 8.314J/mol.K

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles if the gas

R = ideal gas constant

T = temperature of the gas

n = number of moles

n = mass / molar mass

n = 22.1 / 44 = 0.50moles

PV = nRT

P = nRT/ V

P = (0.5 × 8.314 × 85.15) / 0.165

P = 2145.26Pa = 2.145kPa

Pressure of the gas is 2.145kPa

6 0

3 years ago

How many atoms are in 0.0246 mol K?

Alexxx [7]

Answer:

There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K.

Explanation:

3 0

2 years ago

liv sheldon Given the balanced equation for an organic reaction: C2H2 + 2Cl2 → C2H2Cl4 This reaction is best classified as *

Afina-wow [57]

Answer:

An addition reaction

Step-by-step explanation:

In an addition reaction, two or more molecules come together to form a single product, for example,

C₂H₂ + 2Cl₂ ⟶ C₂H₂Cl₄

This reaction consists of two successive additions. The product of the first reaction becomes a reactant and adds a second molecule of Cl₂ to form C₂H₂Cl₄

C₂H₂ + Cl₂ ⟶ C₂H₂Cl₂

C₂H₂Cl₂ + Cl₂ ⟶ C₂H₂Cl₄

C₂H₂ + 2Cl₂ ⟶ C₂H₂Cl₄

4 0

3 years ago

calculate the amount of heat needed to boil 119. g of benzene, beginning from a temperature of 5.9°C.​

calculate the amount of heat needed to boil 119. g of benzene, beginning from a temperature of 5.9°C.