Answer:
Explanation:
ω = √k/m = √(33.9/0.28) = 11 rad/s
(a) maximum speed of the oscillating mass
vmax = ωA = 11(0.05) = 0.55 m/s
(b) speed of the oscillating mass when the spring is compressed 1.5 cm
The portion of total energy that is not spring potential is kinetic
½kA² - ½kx² = ½mv²
v = √(k(A² - x²)/m) = √(33.9(0.05² - 0.015²)/0.28 = 0.52482... ≈ 0.52 m/s
(c) speed of the oscillating mass as it passes the point 1.5 cm from the equilibrium position
Different wording, but same question as part (b) 0.52 m/s
(d) value of x at which the speed of the oscillating mass is equal to one-half the maximum value m
The portion of total energy that is not kinetic is spring potential
½kA² - ½mv² = ½kx²
x = √(kA² - m(vmax/2)²) / k) = √(33.9(0.05²) - 0.28(0.55/2)²) / 33.9)
x = 0.043305...≈ 4.3 cm
Answer:
26 V
Explanation:
Given:
The three resistors 5.5 V. 8.2 V. and 12,3 V. are connected in series.
Now we have to find out the source voltage to which these resistors arc connected ?
Solution:
As we know in series the magnitude of current is uniform but the voltage divides between the resistors supplied from source voltage.So the magnitude of source voltage is, 5.5 V + 8.2 V + 12.3 V = 26 V
Hence, the value of the source voltage to which these resistors are connected is 26 V
Answer:
Answer should be (B)
Explanation:
If the forces on an object are balanced (or if there are no forces acting on it), this is what happens: a stationary object stays still. a moving object continues to move at the same speed and in the same direction.
ALSO: forces acting upon an object are balanced, then the object will maintain its state of motion. To maintain the state of motion is to keep the current speed and direction. But if the forces are not balanced, the object will change its state of motion.
Answer:
A) v_average = - 10 km / h, B) v = 1.6 m / s, v = 17.6 m / s
Explanation:
A) the average speed is the average speed of a body, if we assume that the direction of going up the hill is positive
v₁ = 40 km / h
v₂ = - 60 km / h
the average speed is
v_average =
v_average = ( 40 - 60)/2
v_average = - 10 km / h
B) in this case they indicate the acceleration a = 3.2 m / s² and the velocity vo = 9.6 m / s
i) the speed for 2.5 s above
v = v₀ + a t
as the time is earlier
t = - 2.5 s
we substitute
v = 9.6 - 3.2 2.5
v = 1.6 m / s
ii) the velocity for a subsequent time of 2.5 s
t = 2.5 s
we substitute
v = 9.6 + 3.2 2.5
v = 17.6 m / s