The magnetic moment is -
M = 5.5 x
A
.
We have current carrying single circular loop placed in a magnetic field
parallel to the plane of the loop.
We have to determine the Magnetic moment of the loop.
<h3>What is the formula to calculate the magnetic moment of loop?</h3>
The formula to calculate the magnetic moment of the loop is -
M = NIA
where -
N - Number of turns
I - Current in the loop
A - Area of the loop
According to the question, we have -
I = 17mA = 0.017A
Circumference (C) = 2 meters
B = 0.8 T
Now -
C = 2
2
r = 2
r = 1
r = 
r = 0.32
Using the formula -
M = NIA
M =
NI
M = 3.14 x 1 x 0.017 x 0.32 x 0.32
M = 3.14 x 4 x 0.017
M = 5.5 x
A
Hence, the magnetic moment is -
M = 5.5 x
A
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Let's assume that ground level is the height 0 meters. The change in potential energy is going to be gravitational potential energy, which is given by PE=mgh.
ΔPE=mgh-mgy
=mg(h-y)
=50(28-0)
=1400 J
PE = mgh
m = 60 kg
g = 10 m/s
h = X
_______
3000 = 60×10×X = 5 m
Answer:
Acceleration equals the change in velocity divided by time.
Explanation: