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2 years ago

Interpret the following graphs by answering the questions below.

Physics

1 answer:

Furkat [3]2 years ago

6 0

Answer:

Nodes = 5 and antinodes = 4

Explanation:

Nodes are the points of zero amplitude and appear to be fixed. On the other hand, antinodes are points on a stationary wave that oscillates with maximum amplitude.

In this given standing wave, there are 5 points where the amplitude is 0. So, there are 5 nodes. Also, there are 4 points where the amplitude is maximum.

So, there are 5 nodes and 4 antinodes.

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The space shuttle is accelerated off its launch pad to a velocity of 525 m/s in 18.0 seconds.

Eva8 [605]

Answer: 29.17m/s^2

Explanation:

Given the following :

Velocity = 525 m/s

Time = 18 seconds

Acceleration = change in Velocity with time

Using the motion equation:

v = u + at

Where v = final Velocity

u = Initial Velocity and t = time

Plugging our values

525 = 0 + a × 18

525 = 18(a)

a = 525 / 18

a = 29.166666

a = 29.17 m/s^2

8 0

3 years ago

What is the maximum kinetic energy of ejected electrons when photons of wavelength 300 nm hit a metal that has a work function o

Sonja [21]

Explanation:

Given that,

Wavelength of the photon, $\lambda=300\ nm=3\times 10^{-7}\ m$

Work function of the metal, $\phi=1.13\ eV=1.81\times 10^{-19}\ J$

We need to find the maximum kinetic energy of the ejected electrons. It can be calculated using Einstein's photoelectric equation as :

$hf=E_k+\phi$

$E_k=hf-\phi$

$E_k=h\dfrac{c}{\lambda}-\phi$

$E_k=6.63\times 10^{-34}\times \dfrac{3\times 10^8}{3\times 10^{-7}}-1.81\times 10^{-19}$

$E_k=4.82\times 10^{-19}\ J$

$E_k=3.01\ eV$

$E_k=3\ eV$

So, the maximum kinetic energy of the ejected electrons is 3 ev. Hence, this is the required solution.

3 0

3 years ago

Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a −80-nC charge at x = −4 m on

disa [49]

Answer:

V = 48 Volts

Explanation:

Since we know that electric potential is a scalar quantity

So here total potential of a point is sum of potential due to each charge

It is given as

$V = V_1 + V_2 + V_3$

here we have potential due to 50 nC placed at y = 6 m

$V_1 = \frac{kQ}{r}$

$V_1 = \frac{(9\times 10^9)(50 \times 10^{-9})}{\sqrt{6^2 + 8^2}}$

$V_1 = 45 Volts$

Now potential due to -80 nC charge placed at x = -4

$V_2 = \frac{kQ}{r}$

$V_2 = \frac{(9\times 10^9)(-80 \times 10^{-9})}{12}$

$V_2 = -60 Volts$

Now potential due to 70 nC placed at y = -6 m

$V_3 = \frac{kQ}{r}$

$V_3 = \frac{(9\times 10^9)(70 \times 10^{-9})}{\sqrt{6^2 + 8^2}}$

$V_3 = 63 Volts$

Now total potential at this point is given as

$V = 45 - 60 + 63 = 48 Volts$

3 0

3 years ago

Phoebe's insulated foam cup is filled with 0.15 kg of coffee (mostly water) that is too hot to drink, so she adds

Nesterboy [21]

Answer:

65 Celsius.

Explanation:

8 0

3 years ago

Emily and Gemma did a Reaction time lab. Emily dropped the ruler while Gemma tried to catch it. She caught the ruler 5 times and

dlinn [17]

The average reaction time of Gemma is 0.1564 seconds.

As we know, Gemma is catching the scale and Emily is dropping the scale.

The whole experiment is taking place under gravity, so the acceleration is constant.

As we know, the scale is dropped, it means that the initial velocity of the scale is zero.

We can use the equation of motion,

The equation is,

S = Ut + 1/2at²

Where,

S is the displacement, which is 0.12 m in our case,

U is initial velocity which is 0m/s because the stone is dropped,

t is the time taken, this is equal tot he reaction time here,

a is the acceleration due to gravity whose value is 9.8m/s.

Now, putting all the values,

0.12 = 1/2(9.8)(t)²

t² = 0.24/9.8

t = 0.1564 seconds.

Gemma reacts in 0.1564 seconds to catch the scale.

To know more about equation of motion, visit,

brainly.com/question/27821888

#SPJ1

3 0

1 year ago