Answer:
Heat required to melt 1 lb of ice is 151.469 KJ
Explanation:
We have given mass of ice = 1 lb
We know that 1 lb = 0.4535 kg
Latent heat of fusion for ice =334 KJ/kg
Amount if heat for fusion of ice is given by
, here m is mass of ice and L is latent heat of fusion
So heat 
So heat required to melt 1 lb of ice is equal to 151.469 KJ
Answer:
0.044 V
Explanation:
E = Electric field = 
d = Thickness of membrane = 8 nm
When the electric field strength is multiplied by the membrane thickness we get the voltage
Voltage across a gap is given by
The voltage across the membrane is 0.044 V
The indian ocean is the third largest ocean at 68,556,000 sq km
Wave speed = (wavelength) x (frequency)
Wave speed = (3 m) x (15 Hz)
<em>Wave speed = 45 m/s</em>
