CI2 is the answer to your question
Answer:
The electric force acting on the raindrop is 100 N.
Explanation:
Given;
charge of the raindrop, Q = 10 mC = 0.01 C
electric field strength, E = 10,000 V/m = 10,000 N/C
The force acting on the raindrop is given as;
Electric Force = electric field strength x charge of the raindrop
F = EQ
F = (10,000 N/C) (0.01 C)
F = 100 N
Therefore, the electric force acting on the raindrop is 100 N.
Answer:
Abby is standing (4.5^2 + 2.3^2)^1/2 from the far speaker
D2 = 5.05 m from the far speaker
The difference in distances from the speakers is
5.05 - 4.5 = .55 m (Let y be wavelength, lambda)
n y = 4.5
(n + 1) y = 5.05 for the speakers to be in phase at smallest wavelength
y = .55 m subtracting equations
f = v / y = 340 / .55 = 618 / sec should be the smallest frequency
