Question

Consider the reaction below. 2Al2O3 mc019-1.jpg 4Al + 3O2 How many moles of oxygen are produced if 11.0 mol of Al are produced?

Answer 1

Answer: 8.25 moles of oxygen are produced.

Explanation: The reaction follows:

$2Al_2O_3(s)\rightarrow 4Al(s)+3O_2(g)$

By Stoichiometry,

As, 4 moles of Aluminium is produced by 2 moles of aluminium oxide

11 moles of aluminium will be produced by = $\frac{2}{4}\times 11=5.5moles$

Now, 2 moles of aluminium oxide produces 3 moles of oxygen, so

5.5 moles of Aluminium oxide will produce = $\frac{3}{2}\times 5.5=8.25moles$

Hence, 8.25 moles of oxygen will be produced.

Answer 2

2 Al₂O₃ = 4 Al + 3 O₂

4 moles Al ----------> 3 moles O₂
11.0 moles Al -------> ?

O₂ = 11.0 * 3 / 4

= 8.25 moles of O₂

hope this helps!