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3 years ago

In a plant, 1500kg of nitrogen oxide is consumed per day to produce 1,500 kg of nitrogen per day. What is the prevent yield?

Chemistry

1 answer:

slavikrds [6]3 years ago

5 0

Answer:

65.21 percent

Explanation:

We are to find the percentage yield

We have this equation,

2no+o2 -->2no2

Such that 1500 kilograms/30grams

= Mno2/46

=1500/30 = mno2/46

We cross multiply from here

1500x46 = 30xMnO2

69000 = 30Mno2

69000/30 = MnO2

2300 = Mno2

The percentage yield would be

1500/2300 *100

= 0.6521 x 100

= 65.21%

This answers the question

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At elevated temperatures, methylisonitrile (CH3NC) converts to acetonitrile (CH3CN): CH3NC(g) --> CH3CN(g) At the start of th

pshichka [43]

Answer:

A. 3.7 x 10⁻³

Explanation:

In the beginning of the reaction there are 0.200 moles of reactant. After 25 minutes, remain 0.108 moles. That means the moles that wer descomposed are:

0.200 moles - 0.108 moles = 0.092 moles of reactant were descomposed.

That descomposition occurs in 25 minutes. The average rate of descomposition in moles / minute are:

0.092 moles Methyl isonitrile / 25 minutes = 3.7x10⁻³ mol/min.

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4 years ago

How much work is needed to assemble an atomic nucleus containing three protons (such as Be) if we model it as an equilateral tri

klio [65]

Answer:

2.16 MeV

Explanation:

To determine the amount of work done that is needed to assemble the atomic mass; we need to apply the equation;

U = $\frac{3}{4 \pi E_o} (\frac{e^2}{r})$

where:

$\frac{1}{4 \pi E_o}$ = proportionality constant = $(9*10^9N.m^2/C^2)$

e = magnitude of the charge of each electron = $(1.6*10^{-19} C)^2$

r = length of each side of the vertex = $(2.00*10^{-15}m)$

So; replacing our values into above equation; we have:

U = $3\frac{(9*10^9N.m^2/C^2)(1.6*10^{-19} C)^2}{(2.00*10^{-15}m)}$

U = 3.456 × 10 ⁻¹³ J

If we have to convert our unit from J to Mev; then we are going to have:

U = 3.456 × 10 ⁻¹³ J $(\frac{1 MeV}{1.602*10^{-13}J})$

U = 2.16 MeV

Therefore, the amount of work done needed to assemble an atomic nucleus = 2.16 MeV

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3 years ago

How is the separation of dna like a zipper

Sedbober [7]

The two strands must be separated like the two sides of a zipper, by breaking the weak hydrogen bonds that link the paired bases.

<u>Explanation:</u>

A double helix structure formed by two polypeptide chains is separated like the two sides of a zipper. A zipper is formed by breaking the weak hydrogen bonds that link the paired bases. During replication, an enzyme "Helicase" travels down the DNA and splits the chain and it forms 2 separate strands.

The two DNA strand which has the same sequence must be separated like the two sides of a zipper by breaking weak hydrogen bases. During base pair-rule, the strand are unzipped and each strands is copied.

3 0

3 years ago

The Ksp of CaF2 is 4.0 x 10-11. What is the solubility of CaF2 in 0.10 M Ca(NO3)2? Give your answer using scientific notation an

Ilya [14]

Answer:

$1.0\times 10^{-5} M$ is the solubility of $CaF_2$ in 0.10 M $Ca(NO_3)_2$ .