In a fluid, all the forces exerted by the individual particles combine to make up the pressure exerted by the fluid
Due to fundamental nature of fluids, a fluid cannot remain at rest under the presence of shear stress. However, fluids can exert pressure normal to any contacting surface. If a point in the fluid is thought of as a small cube, then it follows from the principles of equilibrium that the pressure on every side of this unit of fluid must be equal. but if this were not a case, the fluid would move in the directions of the resulting force, So the pressure on a fluid at rest is isotropic.
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There are many. But if this is a chemistry question it’s liquid
The ground exerts an equal force on the golf ball.
GIven data:
Distance between the plates = 1.5 mm
Potential difference V = 600V
Charge on electron q = -1.6× C
mass on electron = m = 9.1× Kg
Solution:
First we will find the change in potential energy of the charge while moving through the potential difference of 600V.
ΔU = qΔV
= (-1.6×)(600)
= -9.6×J
By the law of conservation of mechanical energy, as there is no external force acting, so the sum of the kinetic and potential energies will be a constant.
K + U = E
ΔK + ΔU = 0
ΔK = -ΔU
1/2mv² = -ΔU
v² = -2ΔU/m
=
v =
v = 1.45× m/s
Answer:
If a bulb is rated at 60 W it uses 60 W (60 J/s) for its operation.
If only 18% of this power input provides useful light then the light produced each second is
P = .18 * 60 J / s = 10.8 J / sec
In one sec W = P * t = 10.8 J/s * 1 sec = 10.8 joules