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Julli [10]
3 years ago
11

According to Heisenberg's uncertainty principle, the more we know about a particle's momentum, the less we know about its ______

_.
Physics
1 answer:
Hoochie [10]3 years ago
7 0

Answer:

location.

Explanation:

Heisenberg uncertainty principle states that it is basically impossible to know the exact position and momentum of a particle at the same time. According to my research on this principle, I can say that based on the information provided within the question the more we know of the momentum the less we know about it's location.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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How do you find the kinetic energy of an object? ​
Sergeeva-Olga [200]

Answer:

KE = 1/2 * m * v^{2}

Explanation:

use the formula:

KE = 1/2 * m * v^{2}

KE = kinetic energy in joules (J)

m = mass in kg

v = velocity in m/s

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3 years ago
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If the distance between two charges is doubled, by what factor is the magnitude of the electric force changed? F_e final/F_e, in
motikmotik

To solve this problem we will apply the concepts related to Coulomb's law for which the Electrostatic Force is defined as,

F_{initial} = \frac{kq_1q_2}{r^2}

Here,

k = Coulomb's constant

q_{1,2} = Charge at each object

r = Distance between them

As the distance is doubled so,

F_{final} = \frac{kq_1q_2}{( 2r )^2}

F_{final} = \frac{ kq_1q_2}{ 4r^2}

F_{final} = \frac{1}{4} \frac{ kq_1q_2}{r^2}

F_{final} = \frac{1}{4} F_{initial}

\frac{F_{final}}{ F_{initial}} = \frac{1}{4}

Therefore the factor is 1/4

6 0
3 years ago
Two charges, q1 and q2, are separated by a certain distance r. if the magnitudes of the charges are halved and their separation
vazorg [7]

The electrical force between these two charges remains the same. In coulomb’s law, it states that the magnitude of two charges (product of two charges) is inversely proportional to the square of the distance. Since both the magnitude and the distance are halved, therefore, the change in both quantities will have no effect in the value of electrical force.

6 0
3 years ago
A vessel contains 1 mol of O2 and 2mol of He.what is the value of'Cp/Cv ' of the mixture?
BlackZzzverrR [31]
Oxygen is diatomic, so its degree of freedom, (f1)= 5,
also its number of moles, n1= 1


Helium is monoatomic, so its degree of freedom (f2)= 3 
and its number of moles given is, n2=2

Now using formula of effective degree of freedom of mixture, (f), we have: 

f= (f1n1+f2n2)/(n1+n2)
  =  (5*1 + 3*2)/ (1+3)
   =11/3
Also, from first law of thermodynamics;
U= n Cv. T = nRT(f2)
 or, Cv = R. (f/2) (n & T cancel)

We know f=11/6, 
substituting the value in above relation, we have:

Cv= R. 11/3*2
    = R. 11/6

Also, Cp-Cv = R
 or, Cp- R.(11/6)= R
or, Cp= R(11/6 )+1
          = 17/6 R

Therefore, Cp/Cv = 17/11
    




6 0
3 years ago
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