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3241004551 [841]
3 years ago
15

Which of the following best describes

Physics
2 answers:
TiliK225 [7]3 years ago
8 0
The answer is A as it is more dangerous to the planet.
svlad2 [7]3 years ago
7 0

Answer:

A. harmful substances in the air, water, or soil

hope my ans helps

be sure to follow me

stay safe

have a good day

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The speed of light is greater in a vacuum than in air or water.<br><br> True or false
Dima020 [189]
True !! Hope I helped you out a bit!
7 0
3 years ago
Read 2 more answers
A .5 kg toy train car moving forward at 3 m/s collides with and sticks to a .8 kg toy car that is traveling at 2 m/s what is the
Viktor [21]
Here we have perfectly inelastic collision. Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:
m_{1} * v_{1} + m_{2} * v_{2} = m_{1} * v'_{1}+ m_{2} * v'_{2}

In case of perfectly inelastic collision v'1 and v'2 are same.

We are given information:
m₁=0.5kg
m₂=0.8kg
v₁=3m/s
v₂=2m/s
v'₁=v'₂=x

0.5*3 + 0.8*2 = 0.5*x + 0.8*x
1.5 + 1.6 = 1.3x
3.1 = 1.3x
x = 2.4 m/s
4 0
3 years ago
What factor about the planets caused you to weigh more or less?
ad-work [718]

usually gravity is what causes us to make us weigh more or less depending on which planet we are on

7 0
3 years ago
Which best describes the law of conservation of mass?
Sergio039 [100]

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

7 0
3 years ago
Raindrops acquire an electric charge as they fall. Suppose a 2.4-mm-diameter drop has a charge of +18 pC, fairly typical values.
muminat

To solve this problem we will apply the concepts related to the potential, defined from the Coulomb laws for which it is defined as the product between the Coulomb constant and the load, over the distance that separates the two objects. Mathematically this is

V = \frac{kq}{r}

k = Coulomb's constant

q = Charge

r = Distance between them

q = 18 pC \rightarrow q = 1.8*10^-11 C

d = 2.4mm \rightarrow r = 1.2 mm = 1.2*10^-3 m

Replacing,

V = \frac{kq}{r}

V = \frac{ (9*10^9)*(1.8*10^{-11})}{(1.2*10^{-3})}

V = 135 V

Therefore the potential at the surface of the raindrop is 135 V

3 0
3 years ago
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