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2 years ago

4.2 L of a gas has a pressure of 560mmHg at 72⁰F. What is the temperature at760mmHg if the volume is still 4.2 L? (5 pts)

Chemistry

1 answer:

IgorLugansk [536]2 years ago

8 0

Answer:

The temperature at 760mmHg if the volume is still 4.2 L is 400.862 K

Explanation:

Gay Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. This law can be expressed mathematically as follows:

$\frac{P}{T} =k$

Having an initial state 1 and a final state 2, the following is true:

$\frac{P1}{T1} =\frac{P2}{T2}$

In this case:

P1= 560 mmHg
T1= 72 F= 295.372 K (being 32 F= 273.15 K)
P2= 760 mmHg
T2= ?

Replacing:

$\frac{560 mmHg}{295.372 K} =\frac{760 mmHg}{T2}$

Solving:

$T2= 760 mmHg*\frac{295.372 K}{560 mmHg}$

T2= 400.862 K

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In the molecule NO2 which element is pulling the electrons

Andrei [34K]

The bond between the N and 0 (double bond) transfers and gives a -ve charge on O and a +ve charge on N atom at the group . Thus the +vely charged nitrogen is electron-deficient pulling electrons towards itself!

The combination of the +vely charged nitrogen and the electronegative oxygen atom leads to delocalization causing the resonance effect.

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3 years ago

g If 50.0 mL of a 0.75 M acetic acid solution is titrated with 1.0 M sodium hydroxide, what is the pH after 10.0 mL of NaOH have

V125BC [204]

Answer:

pH = 2.66

Explanation:

Acetic Acid + NaOH → Sodium Acetate + H₂O

First we calculate the number of moles of each reactant, using the given volumes and concentrations:

0.75 M Acetic acid * 50.0 mL = 37.5 mmol acetic acid

1.0 M NaOH * 10.0 mL = 10 mmol NaOH

We calculate how many acetic acid moles remain after the reaction:

37.5 mmol - 10 mmol = 27.5 mmol acetic acid

We now calculate the molar concentration of acetic acid after the reaction:

27.5 mmol / (50.0 mL + 10.0 mL) = 0.458 M

Then we calculate [H⁺], using the following formula for weak acid solutions:

[H⁺] = $\sqrt{C*Ka}=\sqrt{0.458M*1.76x10^{-5}}$

[H⁺] = 0.0028

Finally we calculate the pH:

pH = -log[H⁺]

pH = 2.66

8 0

2 years ago

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of carbon tetrachlori

mario62 [17]

Answer:

0.55mL of carbon tetrachloride

Explanation:

CH4(g) + 2Cl2(g) -------> CCl4(g) + 2H2(g)

From the balanced reaction equation

44800mL of chlorine produces 22400 ml of carbon tetrachloride

If 1.1mL of chlorine were consumed, volume of carbon tetrachloride= 1.1×22400/44800

=0.55mL of carbon tetrachloride

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3 years ago

What is the effect of high activation energy on a chemical reaction?

alex41 [277]

<h3>Answer;</h3>

It makes the reaction harder to start

<h3>Explanation;</h3>

Activation energy is minimum amount of energy that is required for a reaction to start. Activation energy determines the rate of a chemical reaction such that the higher the activation energy, the lower the rate of chemical reaction and vice versa.
The source of activation energy needed to push chemical reactions forward is obtained from the surroundings. Catalyst speed up chemical reaction by lowering the activation energy. Therefore, catalysis is the increase in the rate of a chemical reaction by lowering its activation energy.

4 0

3 years ago

Calculate the entropy change for the reaction: Fe2O3(s) +3C(s) -> 2Fe(s) + 3CO(g)Entropy data:Fe2O3(s): 90 J/K molC(s): 5.7 J

Annette [7]

Explanation:

We are given: entropy of Fe2O3 = 90J/K.mol

: entropy of C = 5.7J/K.mol

: entropy of Fe = 27.2J/K.mol

: entropy of CO = 198J/K.mol

$\begin{gathered} \Delta S\text{ = S}_{products}-S_{reactants} \\ \\ \text{ = \lparen3}\times198+2\times27.2)-(3\times5.7+90) \\ \\ \text{ = 541.3J/K.mol} \end{gathered}$

Answer:

The correct answer is C.

5 0

11 months ago