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forsale [732]
3 years ago
7

How can the starch be removed from the leaves of potted plants​

Physics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

Explanation:

There are two main ways to de-starch leaves of a plant - the 'Light Exclusion' Method and the 'Carbon Dioxide Deprivation' Method. The 'Light Exclusion' method is a simpler procedure and is used often. Leaves can be destarched by depriving them of light for an extended period of time, usually 24-48 hours.

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When an electric stove element is hot enough, it gives off a dull red glow. When it cools to the point that it no longer glows,
DochEvi [55]

Answer:

It will have a longer wavelength

Explanation:

When an electric stove is hot and gives dull red glow. a part of the energy dissipated is emitted as visible light and part as infrared radiation in the form of heat. When the stove cools down, and no longer glows all the energy is now in the form of infrared radiation.In the electromagnetic spectrum infrared rays have a higher wavelength than visible light. Hence for the reason the radiation will have a higher wavelength since visible light is cut off.

4 0
3 years ago
When water freezes, its volume increases by 9.05%. What force per unit area is water capable of exerting on a container when it
AnnZ [28]

Answer:

The Pressure is 0.20 MPa.

(b) is correct option.

Explanation:

Given that,

Change in volume = 9.05%

{tex]\dfrac{\Delta V}{V_{0}}=0.0905[/tex]

We know that.

The bulk modulus for water

B=0.20\times10^{10}\ N/m^2

We need to calculate the pressure difference

Using formula bulk modulus formula

B=\Delta P\dfrac{V_{0}}{\Delta V}

\Delta P=B\dfrac{\Delta V}{V_{0}}

\Delta P=0.2\times10^{10}\times0.0905

\Delta P=0.2\times10^{6}\ Pa

\Delta P=0.20 MPa

Hence, The Pressure is 0.20 MPa.

6 0
4 years ago
Please dont ask people to be "Bf" and "gf" On this app. This is for school. So all of you please be safe!! Thank you.
Ksju [112]
People do that on here?
4 0
3 years ago
Read 2 more answers
Prove dimensionally that: PV=RT
Oduvanchick [21]

Ideal Gas Law PV = nRT

THE GASEOUS STATE
Pressure  atm
Volume  liters
n  moles
R  L atm mol^-1 K^-1
Temperature  Kelvin


pv = rt

divide both sides by v
pv/v = rt/v

p = rt/v

answer: p = rt/v




Ideal Gas Law: Density

PV = NRT
PV = mass/(mw)RT

mass/V = P (MW)/RT = density



Molar Mass:
Ideal Gas Law PV = NRT
PV = mass/(MW) RT
MW = mass * RT/PV


Measures of Gases:
Daltons Law of Partial Pressures; is the total pressure of a mixture of gases equals the sum of the partial pressures of the individual gases.

Total = P_ A + P_ B

P_ A V = n_ A RT

P_ B V = n_ B R T



Partial Pressures in Gas Mixtures:
P_ total = P_ A + P_ B
P_ A = n_ A RT/V P_ B = n_ B RTV

P_ total = P_ A + P_ B = n_ total RT/V




For Ideal Gasses:


P_ A = n_ A RT/V P_ total = n_ toatal RT/V



P_ A/P_ total = n_ A RTV/n_ total RTV


= n_ A/n_ total = X_ A





Therefore, P_ A = X_ A P_ total.



PV = nRT


P pressure

V volume


n Number of moles


R Gas Constant


T temperture (Kelvin.).







Hope that helps!!!!!! Have a great day : )

4 0
3 years ago
Suppose your hair grows at the rate of 1/26 inches per day. Find the rate at which it rows in nanometers per second. Because the
notka56 [123]

Answer:

11.306 nm/s

or

113.06 atomic layers/sec

Explanation:

Hello!

First we need to know how much an inch equals in nanometers and a day in seconds:

Since <em>1inch = 2.54cm</em> and <em>1cm=10^7nm</em>

<em>      </em>1 inch = 2.54 * 10^7 nm<em> </em>

<em />

Also <em>1day = 24hours = 24*60minutes = 24*60*60seconds</em>

<em>    </em>1 day = 86.4 * 10^3 s

Therefore the rate at which the hair grows in nanometers per seconds is:

    1/26 in/day = (1/26) * (2.54*10^7)/(86.4*10^3) = 11.306 nm/s

 

Now, if 1 atomic layer = 0.1 nm this means that 1 nm = 10 atomic layers.

Therefore:

The rate in atomic layers is

11.306 nm/s = 11.306 (10 atomic layers)/s = 113.06 atomic layers/sec

<em />

5 0
3 years ago
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