Another name for the horizontal rows on the periodic table of elements

ASAP WILL GIVE BRAINLIEST!!!

Oksana_A [137]

Answer:

<em>The change in momentum of the car is 3575 Kg.m/s</em>

Explanation:

<u>Impulse and Momentum</u>

The impulse (J) experienced by the object equals the change in momentum of the object (Δp).

The formula that represents the above statement is:

J = Δp

The impulse is calculated as

J = F.t

Where F is the applied force and t is the time.

The car hits a wall with a force of F=6500 N and stops in 0.55 s. Thus, the impulse is:

J = 6500 * 0.55

J = 3575 Kg.m/s

The change in momentum of the car is:

$\Delta p= J = 3575\ Kg.m/s$

The change in momentum of the car is 3575 Kg.m/s

5 0

3 years ago

In general it is best to conceptualize vectors as arrows in space, and then to make calculations with them using their component

JulijaS [17]

Answer:

The calculated vectors are:

$\vec{A}-\vec{B}=(3,-5,-4)$

$\vec{B}-\vec{C}=(-5,4,0)$

$-\vec{A}+\vec{B}-\vec{C}=(-6,4,3)$

$3\vec{A}-2\vec{C}=(-3,-2,-11)$

Explanation:

To operate with vectors, you sum or rest component to component. To multiply scalars with vectors, you distribute the scalar with each component of the vector. These are the following rules you must apply in these cases:

$\vec{V}+\vec{W}=(V_1,V_2,V_3)+(W_1,W_2,W_3)=(V_1+W_1,V_2+W_2,V_3+W_3)$ (1)

$\vec{V}-\vec{W}=(V_1,V_2,V_3)-(W_1,W_2,W_3)=(V_1-W_1,V_2-W_2,V_3-W_3)$ (2)

$\alpha\cdot\vec{V}=\alpha\cdot(V_1,V_2,V_3)=(\alpha\cdot V_1,\alpha\cdot V_2,\alpha\cdot V_3)$ (3)

The operations in these cases are:

$\vec{A}-\vec{B}=(1,0, -3)-(-2,5,1)=(3,-5,-4)$

$\vec{B}-\vec{C}=(-2,5,1)-(3,1,1)=(-5,4,0)$

$-\vec{A}+\vec{B}-\vec{C}=-(1,0, -3)+(-2,5,1)-(3,1,1)=(-6,4,3)$

$3\vec{A}-2\vec{C}=3(1,0, -3)-2(3,1,1)=(3,0, -9)-(6,2,2)=(-3,-2,-11)$

3 0

3 years ago

Read 2 more answers

The following four waves are sent along strings with the same

likoan [24]

Answer:

Explanation:

y_1 = (3 mm) sin(x - 3t)

comparing it with standard wave equation

y = A sin( ωt-kx )

we see

ω = -3 , k = -1

velocity = ω / k

= 3

y_2 = (6 mm) sin(2x - t)

we see

ω = -1 , k = -2

velocity = ω / k

= .5

y_3 = (1 mm) sin(4x - t)

we see

ω = -1 , k = -4

velocity = ω / k

= .25

y_4 = (2 mm) sin(x - 2t)

we see

ω = -2 , k = -1

velocity = ω / k

= 2

So greatest velocity to lowest velocity

y_1 = (3 mm) sin(x - 3t) , y_4 = (2 mm) sin(x - 2t) ,y_2 = (6 mm) sin(2x - t) , y_3 = (1 mm) sin(4x - t)

b )

Given the mass per unit length of wire the same , velocity is proportional to

√ T , where T is tension

so in respect of tension in the wire same order will exist for highest to lowest tension .

3 0

3 years ago

A 9.76-m ladder with a mass of 22.6 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upw

galben [10]

Answer:

Part a)

$\tau_{net} = 1397.1 Nm$

Part b)

$I = 702.06 kg m^2$

Explanation:

Part a)

Torque on the rod is due to two forces

(i) Due to weight of the rod at mid point

(ii) Due to external force applied at the end

Now we have

$\tau_{net} = FL - mg\frac{L}{2}$

$\tau_{net} = 254(9.76) - (22.6)(9.81)(\frac{9.76}{2})$

$\tau_{net} = 1397.1 Nm$

Part b)

As per Newton's law we know that

$\tau = I\alpha$

now we have

$1397.1 Nm = I(1.99 rad/s^2)$

$I = 702.06 kg m^2$

6 0

3 years ago

An electron is traveling horizontally toward the north in a uniform magnetic field that is directed vertically downward. In what

Arte-miy333 [17]

Answer:

e) upwrad z axis

Explanation:

To know the direction of the force we use the right hand rule.

The thumb points in the direction of the velocity, the fingers extended in the direction of the magnetic field and the palm of the hand in the direction of the force, this is for a positive charge if the charge is negative the force is in the opposite direction of The palm of the hand.

Let's apply to our case.

The thumb is in the x direction, the fingers in the vertical direction and since the electron has a negative charge, the force is on the z axis (perpendicular to the blade, coming out)

In general, in the nomenclature of the cardinal points the positive x-axis is the East, the positive y-axis is the North. Therefore the answer must be up on the z axis

8 0

3 years ago