The electric field at any point in the region between the conductors is proportional to the magnitude Q of charge on each conductor. It follows that:
"The potential difference Vab between the conductors is also proportional to Q"
If we double the magnitude of charge on each conductor, the charge density at each point doubles, the electric field at each point doubles, and the potential difference between conductors doubles; however, the ratio of charge to potential difference does not change. This ratio is called the capacitance C of the capacitor:
Given that:
and
Lastly, the capacitance is given by:
Answer:
30-N
Explanation:
Because they are both acting on an object going opposite directions, then you simply subtract the 15 from 45 as 45N of force is stronger than 15N of force.
Resistance = voltage / current.
That's. 120v / 14A = 8.57 ohms.
By the way, voltage doesn't "run through" anything. Current does. That would be the 14 Amps.
Answer:
This difference is kept to a minimum because the resistance in transformers is a few tens of ohms and the resistance of modern voltmeters is of the order of MΩ.
Explanation:
A voltmeter is built by a galvanometer and a resistance in series, this set is connected in parallel to the resistance where the voltage is to be measured, therefore the voltage is divided between the voltmeter and the element to be measured, consequently the measured voltage It is less than the calculated one, since for them the resistance of the voltmeter is assumed infinite.
This difference is kept to a minimum because the resistance in transformers is a few tens of ohms and the resistance of modern voltmeters is of the order of MΩ.