Answer:
The maximum velocity the mass can have if the string is not to break = 29.05 m/s
Explanation:
The force balance in the mass:
The tension in the string must always be equal to the force keeping the mass in horizontal circular motion.
The force keeping the mass in circular motion is given by
F = mv²/r
m = mass of body = 0.4 kg
v = speed of the body in circular motion
r = radius of the circular motion = 0.75 m
Maximum tension the string can withstand will correspond to the maximum velocity of the body in horizontal circular motion
T = F = mv²/r
450 = (0.4)(v²)/(0.75)
v² = 450×0.75/0.4 = 843.75
v = 29.05 m/s
Because almost all of the force is done by the weight of the person and the mechanism of the swing itself, when you push someone you only give them an increase in velocity, the acceleration comes from the weight at first and then from gravity when the person is coming down, which is why we bend our legs when coming down
Answer:
Tires.
Explanation:
There are the few steps which are discussed below should be taken to increase or extend the life of tires.
(1) Avoid fast starts: Fast start of the vehicle will increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.
(2) Avoid fast stop: Fast stop of the vehicle will also increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.
(3) Avoid sharp turns: The alignment of the wheels and tires are in such a way that they work properly when vehicle is drive in a straight path but sharp turn will increase the uneven pressure on the tires will lead to decrease the life of tires.
Therefore, the life of tires can be extend by avoiding all the above mention actions such as fast stop, start and sharp turns.
Answer:
To establish this relationship we must examine the potentials that these forces create. The electrical potential is described by
Ve = k q / r
The potential for strong nuclear force is
Vn (r) = - gs / 4pir exp (-mrc / h)
Where gs is the stacking constant and r the distance between the nucleons,
We can compare these potentials where the force is derived from the relationship
E = -dU / dr
F = q E
Explanation:
