An air bubble with a volume of 5.0 ml is released at the bottom of a lake where the pressure is 3.0 atm. when it reaches the sur

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An air bubble with a volume of 5.0 ml is released at the bottom of a lake where the pressure is 3.0 atm. when it reaches the sur

face, the bubble experiences a pressure of 1.0 atm. formula to use: p1v1 = p2v2 how will the volume of the air bubble change?

Chemistry

1 answer:

Svetradugi [14.3K] · Answer 1 · 2023-02-06T01:43:52+03:00

The new volume of the air bubble that has an initial volume of 5.0 ml released at the bottom of a lake where the pressure is 3.0 atm is 15mL.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated by using the following formula:

P1V1 = P2V2

Where;

P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume

5 × 3 = 1 × V2

15 = V2

V2 = 15mL

Therefore, the new volume of the air bubble that has an initial volume of 5.0 ml released at the bottom of a lake where the pressure is 3.0 atm is 15mL.

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